I want to calculate the value of a & b for "x=110972.*a.*cos(b/2);" & " y=110972.*b.*cos(a/2);" equation where x=500 and y=700. But i can't, Please help me out. Thanks in advance.

clc
clear
x=500;
y=700;
x=110972.*a.*cos(b/2);
y=110972.*b.*cos(a/2);
a=
b=

Answer 1

[Star Strider]

This works:

x = 500;
y = 700;

% a = p(1),  b = p(2)
fn = @(p) norm(x - 110972.*p(1).*cos(p(2)/2)) + norm(y - 110972.*p(2).*cos(p(1)/2));

[ab, fval] = fminsearch(fn, [1 1]);

fprintf(1,'\n\ta = %f\n\tb = %f\n\n',ab)

x2 = 110972.*ab(1).*cos(ab(2)/2)
y2 = 110972.*ab(2).*cos(ab(1)/2)

producing:

  a = 0.004506
  b = 0.006308

x2 =

     500.0003e+000

y2 =

     700.0000e+000