Multiplying a 2d matrix with each slice of 3d matrix

39 vues (au cours des 30 derniers jours)
Søren sønderby
Søren sønderby le 1 Août 2014
Commenté : Ray M le 13 Oct 2021
What is the fastest way multiply a 2d matrix with each slice of a 3d matrix?
x = rand(1000,200);
F = rand(100,1000,10);
b = zeros(100,200,10);
for i = 1:10
b(:,:,i) = F(:,:,i)*x;
end
  2 commentaires
Shravankumar P
Shravankumar P le 2 Août 2014
I would like to have the transposed F. i.e., F=F'; is it possible.
Matt J
Matt J le 4 Août 2014
@Shravankumar
MTIMESX has input flags that let you say whether you want the multiplication with F, F', or F.'

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Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 2 Août 2014
f1 = size(F);
x1 = size(x);
b = reshape(sum(bsxfun(@times,reshape(F,[f1(1),1,f1(2:3)]),...
reshape(x',1,x1(2),[])),3),f1(1),x1(2),[]);
  2 commentaires
Ray M
Ray M le 11 Oct 2021
Great Solution, the solution you have provided is equivalent to:
for i = 1:whatever
b(:,:,i) = F(:,:,i) * x;
end
How would you produce the trasnpose multiplication effect (assuming correct sizes)?
for i = 1:whatever
b(:,:,i) = x * F(:,:,i);
end
Ray M
Ray M le 13 Oct 2021
Nevermind! I got it :)

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Plus de réponses (4)

Steven Lord
Steven Lord le 11 Oct 2021
In release R2020b we introduced the pagemtimes function for this purpose.
  3 commentaires
Ray M
Ray M le 11 Oct 2021
Modifié(e) : Ray M le 11 Oct 2021
I am not sure if this meant to be a reply to my question under Andrei Bobrov solution, but it does not appear so. I am simply interested in performing a single matrix multiplication by slices of a 3D matrix with the use of bsxfun as follows:
mat_mxn * 3Dmat_nxkxl
and
3Dmat_mxnxk * mat_nxh
1) We note that A * B ~= B * A. Note that Andrei Bobrov solution just does 3Dmat_mxnxk * mat_mxh.
2) @times in bsxfun perform .* not * and that is why Andrei Bobrov does a sum as well.
Thanks
Steven Lord
Steven Lord le 12 Oct 2021
@Image Analyst Your bsxfun call is calling times not mtimes. times can work with implicit expansion.
A = int16(magic(4));
B = repmat(A, 1, 1, 3);
C = A.*B
C = 4×4×3 int16 array
C(:,:,1) = 256 4 9 169 25 121 100 64 81 49 36 144 16 196 225 1 C(:,:,2) = 256 4 9 169 25 121 100 64 81 49 36 144 16 196 225 1 C(:,:,3) = 256 4 9 169 25 121 100 64 81 49 36 144 16 196 225 1
mtimes isn't fully defined for integer arrays. If mtimes doesn't work pagemtimes probably shouldn't.
D = A*A % errors
Error using *
MTIMES (*) is not fully supported for integer classes. At least one argument must be scalar.

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Edric Ellis
Edric Ellis le 4 Août 2014
With Parallel Computing Toolbox, you can perform this on the GPU using PAGEFUN.
  1 commentaire
Nils Melchert
Nils Melchert le 19 Mai 2020
Modifié(e) : Nils Melchert le 19 Mai 2020
Is there the possibility to get a minimal example for exactly this use case? I am struggling with the same thing.

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Matt J
Matt J le 2 Août 2014
Modifié(e) : Matt J le 2 Août 2014
See MTIMESX.
  9 commentaires
Matt J
Matt J le 2 Août 2014
Modifié(e) : Matt J le 2 Août 2014
Do you have any experience installing MTIMESX on os x
Don't see why it would be different than Windows, except I'm not sure that SPEEDOMP would be supported. What happens when you try to compile with mtimesx_build?
Søren sønderby
Søren sønderby le 2 Août 2014
It fails with the following output:
Non-PC auto build is not currently supported. You will have to
manually compile the mex routine. E.g., as follows:
>> blas_lib = 'the_actual_path_and_name_of_your_systems_BLAS_library'
>> mex('-DDEFINEUNIX','mtimesx.c',blas_lib)
or
>> mex('-DDEFINEUNIX','-largeArrayDims','mtimesx.c',blas_lib)
I tried to google the blas library path on osx 10.7.5 with no luck so far.

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Image Analyst
Image Analyst le 2 Août 2014
You can do it easily if the number of rows and columns in your 3D and 2D match, which they don't in your example:
rows = 1000;
columns = 200;
slices = 10;
x = rand(rows, columns);
F = rand(rows, columns, slices);
b = zeros(rows, columns, slices);
for slice = 1 : slices
b(:,:, slice) = F(:,:, slice) .* x; % Use dot star, not just star.
end
If the number of rows and columns are different you need to make some decisions about exactly where you want to multiply, if one is smaller than the other, or one extends out past the other.
  1 commentaire
Image Analyst
Image Analyst le 2 Août 2014
Alternate way. Not sure which is faster:
% Mask the 3D image called "image3D" with 2D image called "mask".
masked3DImage = bsxfun(@times, image3D, cast(mask, class(image3D)));

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