MATLAB Answers

Trying to retrieve and display the initial value of an input

8 views (last 30 days)
Ibrahim Ali
Ibrahim Ali on 26 Sep 2021 at 21:13
Commented: Ibrahim Ali on 27 Sep 2021 at 12:53
From disp(q), I'm trying to show the interval chosen at the beginning from x0 to x1, the loop makes it so that x0 and x1 get changed, therefore I'm trying to specify a = the initial value of x0, and b = the initial value of x1, but Matlab gives an error:
Error in sekantH (line 3)
x0 = a;
Does anyone have a solution to this problem I'm having?
-------------------------------
function f = sekantH(f,x0,x1)
x0 = a;
x1 = b;
format long;
tol = 10^-10;
count = 0;
for i = 1:1000
x = x1-f(x1) * (x1-x0)/(f(x1)-f(x0));
count = count+1;
if abs(x1-x)<tol
break
end
x0 = x1;
x1 = x;
f = x;
count;
q = ['Number of iterations on the interval', ' [', num2str(a), ',' ,num2str(b), '] is = ', num2str(count), '. And the root is: '];
disp(q)
end

Accepted Answer

Dave B
Dave B on 26 Sep 2021 at 23:36
Edited: Dave B on 26 Sep 2021 at 23:38
I think you just flipped it, if you want to set a equal to the initial value of x0, do a=x0
demo(5,10)
a=5 b=10 x0=15 x1=30
function demo(x0,x1)
a = x0;
b = x1;
for i = 1:10
x0 = x0 + 1;
x1 = x1 + 2;
end
fprintf('a=%d b=%d x0=%d x1=%d\n',a,b,x0,x1)
end
  1 Comment
Ibrahim Ali
Ibrahim Ali on 27 Sep 2021 at 12:53
You were correct, I had just flipped it! Works beautifully now, thank you!

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by