Input a variable into a plot title

3 349 vues (au cours des 30 derniers jours)
Luke
Luke le 10 Sep 2014
I've trawled through these forums and found loads on inputting variables as titles, however, none of them work for me. Im trying to change the title of a plot with respect to a parameter the user will enter in the function. First i call a string for example
str = sprintf('just an example of %d that isnt working', variable)
title(str)
However only the 'just an example of' is printed out on the title of the plot, everything after and including the variable has dissapeared, this happens when i move the variable about in the title too.
Cheers!
  3 commentaires
Soumitra Vadnerkar
Soumitra Vadnerkar le 26 Sep 2017
Modifié(e) : Walter Roberson le 26 Sep 2017
How about this, given in help documentation:
figure
plot((1:10).^2)
f = 70;
c = (f-32)/1.8;
title(['Temperature is ',num2str(c),' C'])
Alan Keenan
Alan Keenan le 21 Mai 2020
The answer given by Soumitra Vadnerkar works well for me.

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Réponse acceptée

Steven Lord
Steven Lord le 22 Mai 2019
With the introduction of the string array in release R2016b (and the ability to enclose text data in double quotes to create a string in release R2017a) you can also use:
plot((1:10).^2)
f = 70;
c = (f-32)/1.8;
title("Temperature is " + c + " C")
  1 commentaire
Giuseppe Degan Di Dieco
Giuseppe Degan Di Dieco le 21 Oct 2021
Brilliant and easy, thanks!
Best.

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Plus de réponses (2)

MathWorks Support Team
MathWorks Support Team le 22 Mai 2019
How about this, given in help documentation:
plot((1:10).^2)
f = 70;
c = (f-32)/1.8;
title(['Temperature is ',num2str(c),' C'])
  2 commentaires
MathWorks Support Team
MathWorks Support Team le 22 Mai 2019
Thanks Soumitra Vadnerkar for this answer.
Giuseppe Degan Di Dieco
Giuseppe Degan Di Dieco le 21 Oct 2021
Thank you for highlighting the documentation's content to beginners!
Best.

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Adam
Adam le 10 Sep 2014
title( ['just an example of ' num2str( variable ) ' that isnt working'] )
Does that work?
  8 commentaires
Walter Roberson
Walter Roberson le 14 Fév 2017
sprintf() would work fine in R2013* . However, the example given
str = sprintf('just an example of %d that isnt working', variable)
would be best for the case where the variable is an integer. If you have a variable that is numeric but not an integer, you would use a %e or %f or %g format.
Adam
Adam le 14 Fév 2017
sprintf is definitely a neater approach. Back in 2014 I was less familiar with using sprintf so it didn't spring to mind for this!

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