How to go back to the input in a if?

%M=Righe della matrice A
m=4;
%N=Colonne della matrice A
input('n')
for i=1:4
    for j=1:n
        if (n<=13)&&(n>=3)
            disp (['Il numero delle colonne scelto rispecchia le condizioni' ...
                'imposte'])
        else
            disp(['Il numero di colonne da voi scelto non rispecchia le condizioni' ...
                'imposte']); 
            break
        end
    end
end
A(i,j)=input('elementi-');
disp(A)

This is a code about the creation of a Matrix. I'm practising on MatLAB for an IT Exam at University. In this section I'm choosing the number of coloumns, that should be between 3 and 13. I don't know why it stucks on if and how I call again the input after the else. Can anyone help me?

Thanks for the answer.

Regards,

Luigi

Answer 1

[Luigi Bucci]

%M=Righe della matrice A
M=4;
%N=Colonne della matrice A
N=input('n');
for i=1:4
    for j=1:N
        if (N<=13)&&(N>=3)
            disp('Numero di colonne sufficienti, inizio formazione matrice');
            A(i,j)=input('elementi-');
            disp(A)
        else 
            disp('Numero di colonne insufficienti, riavviare il programma');
            return
        end
    end
end

My solution to the issue after writing this part again.

Answer 2

[DGM]

This is a start

%M=Righe della matrice A
m = 4;

%N=Colonne della matrice A
nrange = [3 13];  % pull parameters out for flexibility
while true
    % use descriptive prompts with a trailing space to improve readability
    n = input('Specify the number of columns (%d-%d): ',nrange(1),nrange(2)); 
    if (n<=nrange(2)) && (n>=nrange(1))
        % Unless an affirmative message is required for the assignment, I would consider it redundant
        %disp (['Il numero delle colonne scelto rispecchia le condizioni' ...
        %	'imposte'])
        break;
    else
        disp(['Il numero di colonne da voi scelto non rispecchia le condizioni' ...
            'imposte']);
    end
end

% enter elements columnwise
for j = 1:n
    for i = 1:m
        A(i,j) = input(sprintf('Enter A(%d,%d): ',i,j));
    end
end
disp(A)

[Luigi Bucci]

Thanks for the help, I'm testing it. About the messages, they are required by my IT Teacher, cause, if the messages are missing, he doesn't understand the script, so he will valutate the work done with a low score, that means a low mark for the exam.

[Luigi Bucci]

I solved after re-writing it, this is the code:

%M=Righe della matrice A
M=4;
%N=Colonne della matrice A
N=input('n');
for i=1:4
    for j=1:N
        if (N<=13)&&(N>=3)
            disp('Numero di colonne sufficienti, inizio formazione matrice');
            A(i,j)=input('elementi-');
            disp(A)
        else 
            disp('Numero di colonne insufficienti, riavviare il programma');
            return
        end
    end
end

Now it works perfectly and solves all the doubts.

I add it as a useful hint for someone else. Thanks for your help.

Good evening. Regards,

Luigi