shift matrix to the right

2 vues (au cours des 30 derniers jours)
Nimasha Pilippange
Nimasha Pilippange le 26 Fév 2022
Hello,
I need to compare 2 matrices. One is 1x1280 and other is 1x5120. So I need to take the 1st one to the other range. How do i do that.
for example: A=[0 0 1 1 0 0 1 1], B=[0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1]. The number of elements in B is an integer multiple of number of elements in A. After shifting I need to subtract A by B.
Any Idea?
  7 commentaires
Nimasha Pilippange
Nimasha Pilippange le 27 Fév 2022
Yes I think we need scaling too. Once I get both the data in one range I need to susbstrat one from another. I attached the images again. Let me know if there is any more detail you need.
Image Analyst
Image Analyst le 27 Fév 2022
You forgot to answer my question. Which is it: 1 or 2?

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Réponse acceptée

Image Analyst
Image Analyst le 27 Fév 2022
Try this:
markerSize = 30;
% Say a goes from 250 to 4800 and has 60 elements
a = 250 + (4800-250) * rand(1, 60);
% Say b goes from 100 to 900 and has 30 elements
b = 100 + (900-100) * rand(1, 30);
plot(a, 'b.-', 'LineWidth', 2, 'MarkerSize', markerSize);
hold on;
plot(b, 'c.-', 'LineWidth', 2, 'MarkerSize', markerSize);
grid on;
% Rescale b so that it also goes from 250 to 4800
b = rescale(b, min(a), max(a));
% Interpolate b so that it has the same number of elements as a.
bq = linspace(1, length(b), length(a));
b2 = interp1(b, bq);
plot(b2, 'r.-', 'LineWidth', 2, 'MarkerSize', markerSize);
% Find differences
c1 = a - b2;
c2 = b2 - a;
legend('a', 'b', 'b2')
  1 commentaire
Nimasha Pilippange
Nimasha Pilippange le 28 Fév 2022
I used this and it seems working. Thank you very much

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Plus de réponses (3)

Scott MacKenzie
Scott MacKenzie le 26 Fév 2022
Modifié(e) : Scott MacKenzie le 26 Fév 2022
Perhaps this is what you are looking for:
A=[0 0 1 1 0 0 1 1]
A = 1×8
0 0 1 1 0 0 1 1
B=[0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1]
B = 1×16
0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1
m = numel(A);
n = numel(B);
Anew(n-m+1:n) = A % shifted to match B with zeros at beginning
Anew = 1×16
0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 1

Image Analyst
Image Analyst le 26 Fév 2022
It appears no one knows what you mean since it's not clearly explained and you didn't give the resulting difference vector. So here is another guess:
A=[0 0 1 1 0 0 1 1];
B=[0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1];
% Resize smaller vector to be the same size as the larger vector.
a2 = imresize(A, size(B), 'nearest')
% "subtract A by B" - whatever that means. Here are two possibilities
c = a2 - B
c = B - a2
Let me know if either of these is what you want.

Voss
Voss le 27 Fév 2022
Maybe use interp1() (or resample()):
nx = 20;
x = randn(1,nx);
% xr = resample(x,4,1);
xr = interp1(1:nx,x,1:0.25:nx);
figure();
plot(1:nx,x,'-o');
hold on
plot(0.25*(4:numel(xr)+3),xr,'.');
legend({'Original','Interpolated x4'})

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