Query regarding for loop
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have the below logic
T1 = linspace(10, 800, 10);
for range1 = 1:numel(T1)
a = 2*Mc*(((mde*kb*T1(range1))/(2*pi*(hbar^2)))^(3/2));
b = 2*(((mdh*kb*T1(range1))/(2*pi*(hbar^2)))^(3/2));
c = (kb*T1(range1))/e;
d = 1.17 - (8.096e-8*((T1(range1))^2))/(T1(range1) + 800);
ec1 = d;
ed1 = ec1 + Edi;
eq = @(EF1) ((a)*exp(-(ec1-EF1)/c)) + ((NA1)/(1+4*exp(-(EF1-ea1)/c))) - (((b)*exp(-(EF1-ev1)/c)) + ((ND1)/(1+2*exp(-(ed1-EF1)/c))));
x = [0 2];
Eflevel1(range1) = fzero(eq, x);
end
%How can I write the above lines without using for loop? Is that possible?
%Assume all other values as constants.
2 commentaires
Réponses (1)
Walter Roberson
le 14 Mar 2022
Q = @(v) sym(v);
syms Edi EF1 e ea1 ev1 hbar kb Mc mde mdh NA1 ND1 T1
assume([Edi, EF1, e, ea1, ev1, hbar, kb, Mc, mde, mdh, NA1, ND1, T1] ~= 0)
Pi = Q(pi);
range1 = 1;
T1vals = linspace(10, 800, 10);
a = 2*Mc*(((mde*kb*T1(range1))/(2*Pi*(hbar^2)))^(3/2));
b = 2*(((mdh*kb*T1(range1))/(2*Pi*(hbar^2)))^(3/2));
c = (kb*T1(range1))/e;
d = Q(1.17) - (Q(8.096e-8)*((T1(range1))^2))/(T1(range1) + Q(800));
ec1 = d;
ed1 = ec1 + Edi;
eq = ((a)*exp(-(ec1-EF1)/c)) + ((NA1)/(1+4*exp(-(EF1-ea1)/c))) - (((b)*exp(-(EF1-ev1)/c)) + ((ND1)/(1+2*exp(-(ed1-EF1)/c))));
sol = solve(eq, EF1, 'returnconditions', true)
sc = subs(sol.conditions, sol.parameters(1), 0)
sz = solve(sc, sol.parameters(2))
sol_EF1 = subs(sol.EF1, {sol.parameters(1), sol.parameters(2)}, {0, sz})
1 commentaire
Walter Roberson
le 14 Mar 2022
The solutions involve roots of an equation of degree 4. I believe it is a polynomial, so I believe that explicit solutions are possible -- though they would be very long !
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!