Incorrect use of '=' operator for an IF statement

I am trying to run a for loop which will collect values 5 values before and 5 value after a certain level.

At the minute when the code looks for the next 5 values it exceeds the array, therefore I have tried to create an if statement that will only search for the 5 values before is the index exceeds the array.

At the minute the if and elseif statement recieves this error message

File: Increasing_Code.m Line: 79 Column: 30

Incorrect use of '=' operator. Assign a value to a variable using '=' and compare values for equality using '=='.

This is what I have so far.

Level_Either_Side = [];
for p = 1:length(Componentry_New);
    if Position(1,p)+5 > length(Componentry_New)
        Level_Either_Side = [Level_Either_Side Sorted_Level(Position(1,p)-5:Position(1,p),1)];
    elseif  Level_Either_Side = [Level_Either_Side Sorted_Level(Position(1,p)-5:Position(1,p)+5,1)];
    end
end

If anybody nows where the mistake I have made is that would be greatly apprieciated.

Answer 1

[Star Strider]

I usually do something like this in setting an index range —

L = numel(Componentry_New)

for k = 1:Whatever

Level_Either_Side = max(1,Level_Either_Side Sorted_Level(Position(1,p)-5) : min(Position(1,p)+5,L);

ThisIteration{k} = SomeFunction(Componentry_New(Level_Either_Side));

end

Illustrating this approach —

v = randi(9,1,10)

v = 1×10

8 4 8 5 8 7 6 7 5 6

L = numel(v);
for k = 1:9
    idxrng = max(1,k-3) : min(k+3,L)
    q = v(idxrng)
    fprintf('\n----------\n')
end

idxrng = 1×4

1 2 3 4

q = 1×4

8 4 8 5

----------

idxrng = 1×5

1 2 3 4 5

q = 1×5

8 4 8 5 8

----------

idxrng = 1×6

1 2 3 4 5 6

q = 1×6

8 4 8 5 8 7

----------

idxrng = 1×7

1 2 3 4 5 6 7

q = 1×7

8 4 8 5 8 7 6

----------

idxrng = 1×7

2 3 4 5 6 7 8

q = 1×7

4 8 5 8 7 6 7

----------

idxrng = 1×7

3 4 5 6 7 8 9

q = 1×7

8 5 8 7 6 7 5

----------

idxrng = 1×7

4 5 6 7 8 9 10

q = 1×7

5 8 7 6 7 5 6

----------

idxrng = 1×6

5 6 7 8 9 10

q = 1×6

8 7 6 7 5 6

----------

idxrng = 1×5

6 7 8 9 10

q = 1×5

7 6 7 5 6

----------

Using the min and max functions this way guarantees thet the indices referenced in ‘Level_Either_Side’ never exceeds the index range of the vector being referenced.

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