Code to determine a log of the mean for a column of numbers?

I actually could do with code to produce the following -I have a dataset and need a results table presenting the log of the mean, maximum and average for four different columns of numbers. So for column 1 - log of the mean, 2 - maximum, 3 - average, 4 - average.

[Walter Roberson]

is "log average" the log of the mean, or the mean of the log?

For example what would it be for [1 2 3] ?

[Gregor Massie]

its the log of the mean! I'll edit my question to reflect that

[dpb]

"for four different columns of numbers..."

So there are 4xN values total or just N?

And, what is

"for column 1 - log of the mean, 2 - maximum, 3 - average, 4 - average."

the duplicate of the last two intended to be?

[Gregor Massie]

the duplicate is just another indice that we require the average for

Answer 1

[Les Beckham]

A = magic(4)

A = 4×4

16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1

logmean_col1 = log(mean(A(:,1)))

logmean_col1 = 2.1401

max_col2 = max(A(:,2))

max_col2 = 14

mean_col3 = mean(A(:,3))

mean_col3 = 8.5000

mean_col4 = mean(A(:,4))

mean_col4 = 8.5000

[Walter Roberson]

A = randi(9, [5 4])

A = 5×4

8 1 6 8 3 2 6 3 5 4 1 1 6 4 7 4 8 8 3 7

table(log(mean(A,1)).', max(A,[],1).', mean(A,1).')

ans = 4×3 table
     Var1     Var2    Var3
    ______    ____    ____

    1.7918     8        6 
     1.335     8      3.8 
    1.5261     7      4.6 
    1.5261     8      4.6 

The ,1 are telling it to perform the operations "along dimension #1"

[Gregor Massie]

Thanks guys, thats great! I'm now looking for code to calculate the anitlog for the first column of numbers? I actually missed out this step, for the first column we calculatye the antilog for each number then work out the log of the mean for the whole column

[Walter Roberson]

exp() for the antilog