How to substract a value from each row in a cell in Matlab?
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I have a cell with dimension 41X41 as shown below
that has values equal to 1, it means all its values are equal to ones as shown below:
Based on many values, I could not include it here in one figure, but its dimension is 41 x 41.
What I was trying to do is calculate the number of ones in each row minus one as shown in the snippet of line code below:
ccc = sum(isSmaller{cc,:} == 1)-1
In order to get 1 row with 40 columns that have 40s. as shown below:
My problem is instead of 40 columns is still showing 41 columns as indicated below.
May I get assistance, please? I need it to be 1 row with 40 columns. After that, I need to sum all the 40s in this ccc = 1x40.
Below is my try:
for cc = 1:length(isSmaller)
ccc = sum(isSmaller{cc,:} == 1)-1
end
2 commentaires
Soufian MELLAHI
le 22 Sep 2022
Hello,
I think you misunderstand that the size of your table is 41 by dimension since it's square. I am not sure to understand your problem. Anyways if you want to fetch daya from ii to jj you can just do it simply like : tmp=ccc(ii:jj);% tampon variable ccc=tmp;% retrieval of desired dimension you can just replace ii and jj by the indexes from where ypi want to extract data. For instance ii=1 & jj=40 to extract the first 40 elements of your row vector.
I hope it answers your question
Réponses (1)
Soufian MELLAHI
le 22 Sep 2022
Modifié(e) : Soufian MELLAHI
le 22 Sep 2022
Hello, I think you misunderstand that the size of your table is 41 by dimension since it's square. I am not sure to understand your problem. Anyways if you want to fetch data from ii to jj you can just do it simply like : tmp=ccc(ii:jj);% tampon variable ccc=tmp;% retrieval of desired dimension you can just replace ii and jj by the indexes from where ypi want to extract data. For instance ii=1 & jj=40 to extract the first 40 elements of your row vector. I hope it answers your question
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