# Im trying to use the integral function without any success...

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Edward Ekman on 6 Oct 2022
Commented: Edward Ekman on 6 Oct 2022 Im trying to use integral to solve the following equation with the bounds from 1 to 4.
I managed to write this as (exp(-(t/3)).* sin(t^2)).
When i enter this in matlab as: I get the following output : While my calculator gives me the following??? What am i not getting right here??

Walter Roberson on 6 Oct 2022
In the symbolic toolbox, int() and solve() attempt to give indefinitely precise closed-form solutions. If int() is not able to find a closed form solution then it returns the integral unevaluated. If you want numeric results, use vpaintegral() or vpasolve() respectively, or vpa() the result of the int() call, or double() the result of the int() call
format long g
syms t
f = (exp(-(t/3)).* sin(t^2))
f = d = int(f, t, 1, 4)
d = vpa(d)
ans =
0.26625810440816920193698247934548
double(d)
ans =
0.266258104408169
vpaintegral(f, t, 1, 4)
ans =
0.266258
Edward Ekman on 6 Oct 2022
Thank you for a fast and well written responce :)

Davide Masiello on 6 Oct 2022
syms t
f = exp(-t/3)* sin(t^2);
I = int(f,t,1,4)
I = This means int cannot compute the value of the definite integral. You could numerically approximate the integral by using vpa.
Fvpa = vpa(I)
Fvpa =
0.26625810440816920193698247934548
Edward Ekman on 6 Oct 2022
Thank you for a fast and well written responce :)