Run a function inside a for loop 10,000 times and record the 3 separate outputs for each trial

I'm very new to MATLAB and I'm trying to import a function and run it 10,000 times inside a for loop.

The function produces 3 separate outputs and I need to record each output from each trial in an array so that I can then pull the mean value from each array. However I cannot get it to work. Here is for loop I have currently.

Please help.

for trials = 1:10000
    [S,M,L] = crayonBreak();
    Sl = [Sl; S];
    Ml = [Ml; M];
    Ll = [Ll; L];
end

[Stephen23]

Important: https://www.mathworks.com/help/matlab/matlab_prog/preallocating-arrays.html

Answer 1

[VBBV]

Sl(trials) =  S;
  Ml(trials) = M;
  Ll(trials) = L;

[VBBV]

Outside of the for loop you can then use mean to compute the mean value of arrays

mean(S1)
mean(M1)
mean(L1)

[Kate]

When I try that it still only shows one value for Sl, Ml, and Ll. I need it to store all 10,000 for each.

[VBBV]

I need to record each output from each trial in an array so that I can then pull the mean value from each array

As mentioned in your question, mean will give only value for any length of array. Do you look at Sl, Ml, Ll arrays below ? they are 1 x 10000 it implies all 10000 values are stored in those arrays as shown below

for trials = 1:10000
    [S,M,L] = crayonBreak();
  Sl(trials) =  S;
  Ml(trials) = M;
  Ll(trials) = L;
end
Sl, Ml, Ll,

Sl = 1×10000

0.6659 0.6360 0.1235 0.2869 0.8678 0.8752 0.2682 0.3422 0.1486 0.7197 0.4954 0.7328 0.3132 0.1744 0.7686 0.2773 0.2526 0.6079 0.7764 0.9991 0.8646 0.9189 0.0676 0.4408 0.2586 0.1732 0.3026 0.3628 0.3977 0.1412

Ml = 1×10000

0.6169 0.9453 0.6292 0.7253 0.2442 0.9436 0.7622 0.3416 0.7905 0.5936 0.7303 0.8699 0.3346 0.3015 0.8931 0.6656 0.1587 0.0749 0.9722 0.6737 0.6742 0.2671 0.5881 0.4916 0.3278 0.3150 0.0546 0.2817 0.9364 0.3957

Ll = 1×10000

0.9494 0.9364 0.2546 0.4788 0.3378 0.0563 0.8846 0.2533 0.4457 0.5506 0.6268 0.2566 0.4805 0.3051 0.2895 0.0662 0.4002 0.2488 0.2092 0.6633 0.6558 0.5478 0.6782 0.9287 0.8313 0.2034 0.0531 0.5057 0.3346 0.1618

mean(Sl)

ans = 0.5024

mean(Ml)

ans = 0.5034

mean(Ll)

ans = 0.5003

function [S,M,L] = crayonBreak()
   S = rand(1);
   M = rand(1);
   L = rand(1);
end

Answer 2

[Stephen23]

Assuming that each output is a scalar double:

N = 1e4;
S = nan(1,N);
M = nan(1,N);
L = nan(1,N);
for k = 1:N
    [S(k),M(k),L(k)] = crayonBreak();
end

Now lets calculate the mean of one of those vectors:

display(S)

S = 1×10000

0.7019 0.0534 0.8125 0.5301 0.4659 0.2806 0.3872 0.4478 0.5410 0.4365 0.1543 0.6310 0.8740 0.9585 0.0317 0.5657 0.8402 0.4991 0.9272 0.1651 0.6194 0.1985 0.2538 0.7495 0.7372 0.7060 0.3727 0.0894 0.7250 0.6181

mean(S)

ans = 0.4969

function [S,M,L] = crayonBreak()
S = rand(1);
M = rand(1);
L = rand(1);
end