How can i delete max values for each 5 rows in vector

1 vue (au cours des 30 derniers jours)
abdullah al-dulaimi
abdullah al-dulaimi le 29 Déc 2022
Commenté : Star Strider le 29 Déc 2022
i have this vector A= 1 14 4 23 3 8 9 12 4 5 2 4 19 20 22
A=A'
The result will be R= 1 14 4 3 8 9 4 5 2 4 19 20

Réponse acceptée

Star Strider
Star Strider le 29 Déc 2022
This looks like homework, however I need something to do this morning —
A = [1 14 4 23 3; 8 9 12 4 5; 2 4 19 20 22];
I = A<max(A,[],2); % Logical Matrix
for k = 1:size(A,1)
R(k,:) = A(k,I(k,:)); % Loop Necessary To Preserve Structure
end
R
R = 3×4
1 14 4 3 8 9 4 5 2 4 19 20
.
  2 commentaires
abdullah al-dulaimi
abdullah al-dulaimi le 29 Déc 2022
vector please don't convert to matrix
Star Strider
Star Strider le 29 Déc 2022
Now the transpose makes snese, with respect to ‘rows’.
Convert it to a matrix for the comparison, then back —
A= [1 14 4 23 3 8 9 12 4 5 2 4 19 20 22];
A = A.';
A = reshape(A,[],3);
for k = 1:size(A,2)
R(:,k) = A(A(:,k)<max(A(:,k)),k);
end
R = R(:).'
R = 1×12
1 14 4 3 8 9 4 5 2 4 19 20

Connectez-vous pour commenter.

Plus de réponses (1)

Davide Masiello
Davide Masiello le 29 Déc 2022
Modifié(e) : Davide Masiello le 29 Déc 2022
The following code will apply to any lenght of A and any length N of window from which to delete the maximum, provided that length(A)/N is an integer.
A = [1 14 4 23 3 8 9 12 4 5 2 4 19 20 22];
R = rmvMaxEveryN(A,5)
R = 1×12
1 14 4 3 8 9 4 5 2 4 19 20
function out = rmvMaxEveryN(array,N)
[~,idx] = max(reshape(array,[N,length(array)/N]),[],1);
idx = idx+(0:N:length(array)-N);
array(idx) = [];
out = array;
end
  3 commentaires
abdullah al-dulaimi
abdullah al-dulaimi le 29 Déc 2022
check the results above
Davide Masiello
Davide Masiello le 29 Déc 2022
Sorry I realised later there was a mistake and adjusted my answer.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by