Reading uint8 from raw data takes much more RAM then expected

2 vues (au cours des 30 derniers jours)
Jonas
Jonas le 18 Jan 2023
Commenté : Jonas le 19 Jan 2023
I am trying to read some MB of data from big files of several GB. I am using the follwing code:
fid=fopen(filename,'r');
fseek(fid,someStartValue,'bof');
raw = fread(fid, [3 ceil(numOfPixels/2)*numOfFrames],'uint8','b');
number of uint8 are
3*ceil(numOfPixels/2)*numOfFrames=184688640
so this is also the value in bytes, corresponding to about 185MB. But when calling the fread line, the taken RAM increases by 1.6 GB.
Any ideas?
Running the fread line mutiple times in a row gives the peaks shown in the attached image. I also don't understand, why there is more RAM available after the peak compared to before the peak. The image shows three calls of the line
  4 commentaires
Les Beckham
Les Beckham le 18 Jan 2023
Modifié(e) : Les Beckham le 18 Jan 2023
That should fix your issue. If you specify the precision argument as 'uint8' as your initial post shows, it will take the uint8 source data and put it into doubles. Using 'uint8=>uint8' will keep the data as uint8, reducing the memory usage by a factor of 8. As Image Analyst suggests in his answer, use the whos command to check the data type and memory size of your raw array after you read it in .
Jonas
Jonas le 19 Jan 2023
issue solved, thanks.

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Réponses (1)

Image Analyst
Image Analyst le 18 Jan 2023
Put the memory command before and after your code. What do you see? Are you sure you're closing the file?
memory
fid=fopen(filename,'r');
fseek(fid,someStartValue,'bof');
raw = fread(fid, [3 ceil(numOfPixels/2)*numOfFrames],'uint8','b');
fclose(fid);
whos raw
memory

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