How do I multiply the numbers in a 2D array using a for loop, must be a for loop as part of the course requirements

2 vues (au cours des 30 derniers jours)
Hi everyone, this is very basic stuff but I'm new to this. All the steps so far are required by the course.
B=[1:24]
B=reshape(B,6,4)'
A1=B(:,4)
A2=B([2 4],[1 4])
B([3 4],[5 6])=[0 1;1 0]
The next step it to 'create a matrix A3 (using a for/end loop) that has coefficients which are the square of the sine of the corresponding values in matrix B (in degrees), eg. if B(2,3)=20, then A3(2,3)=0.1170',
Now, I'm ok with the sin^2 bit, I managed to get an array with but not using a for loop.
>> sin(B*pi/180).^2
ans =
0.0003 0.0012 0.0027 0.0049 0.0076 0.0109
0.0149 0.0194 0.0245 0.0302 0.0364 0.0432
0.0506 0.0585 0.0670 0.0760 0 0.0003
0.1060 0.1170 0.1284 0.1403 0.0003 0
We need to know how to use the for loop for this for later stage work.
Any help would be greatly appreciated, thank you

Réponse acceptée

Matt J
Matt J le 29 Jan 2023
Modifié(e) : Matt J le 29 Jan 2023
One way:
A3=nan(size(B));
for i=1:size(B,2)
A3(:,i)=sind(B(:,i)).^2;
end
  3 commentaires
Matt J
Matt J le 30 Jan 2023
Modifié(e) : Matt J le 30 Jan 2023
size(B,2) gives the number of columns B(:,i).
B=rand(3,5)
B = 3×5
0.3184 0.4519 0.5605 0.1580 0.3940 0.8615 0.8785 0.7961 0.3876 0.0718 0.1113 0.6686 0.2878 0.3678 0.8770
size(B,2)
ans = 5

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