Index exceeds the number of array elements. Index must not exceed 1.

3 vues (au cours des 30 derniers jours)
Alina Abdikadyr
Alina Abdikadyr le 8 Fév 2023
Commenté : Les Beckham le 8 Fév 2023
Could you please help me to solve the problem. I'm trying to calculate the difference between heights in a loop.
But it gives error "Index exceeds the number of array elements. Index must not exceed 1."
My code is
clear all; close all
W = 10000;
S = 40;
AR = 7;
cd0 = 0.005;
k = 1 / pi / AR;
j=0;
hv=6:-.01:0;
figure(1);hold on; xlabel('h');ylabel('V')
for h1=6:-.01:0
j=j+1;
cdminp=4*cd0;
rho1(j)=1.225*exp(-h1/10.4);
clminp=sqrt(3*cd0/k);
Vminp(j)=sqrt(2*W/rho1(j)/S/clminp);
dh(j)=h1(j)-h1(j+1);
end
figure(1); plot(hv, Vminp);
set(gca, 'XDir','reverse');
  4 commentaires
Alina Abdikadyr
Alina Abdikadyr le 8 Fév 2023
Thank you! I want to calculate the difference between the first element and the folloing elements.
If my h1=6:-.01:0
Probably I should write as:
dh=h1(1)-h1(j+1);
so I need to get the values of dh = 0.01;0.02;0.03;0.04 and so on
Les Beckham
Les Beckham le 8 Fév 2023
If you know what the h1 vector is already, you don't need a loop to calculate the accumulated difference between elements of it.
h1=6:-.01:0;
dh = -cumsum(diff(h1));
dh(1:10) % look at the first ten elements
ans = 1×10
0.0100 0.0200 0.0300 0.0400 0.0500 0.0600 0.0700 0.0800 0.0900 0.1000

Connectez-vous pour commenter.

Réponses (1)

Dyuman Joshi
Dyuman Joshi le 8 Fév 2023
You can do that without the loop
W = 10000;
S = 40;
AR = 7;
cd0 = 0.005;
k = 1 / pi / AR;
hv = 6:-.01:0;
cdminp = 4*cd0;
clminp = sqrt(3*cd0/k);
rho1 = 1.225.*exp(-hv./10.4);
Vminp = (2.*W./rho1./S).^(1/2);
dh = hv(1)-hv(2:end)
dh = 1×600
0.0100 0.0200 0.0300 0.0400 0.0500 0.0600 0.0700 0.0800 0.0900 0.1000 0.1100 0.1200 0.1300 0.1400 0.1500 0.1600 0.1700 0.1800 0.1900 0.2000 0.2100 0.2200 0.2300 0.2400 0.2500 0.2600 0.2700 0.2800 0.2900 0.3000
figure(1);
hold on;
xlabel('h');ylabel('V')
plot(hv,Vminp)
set(gca, 'XDir','reverse');

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Tags

Produits


Version

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by