Inverse of a matrix

9 vues (au cours des 30 derniers jours)
L'O.G.
L'O.G. le 16 Mai 2023
Modifié(e) : Matt J le 16 Mai 2023
I want to solve the following for X2: A = B(X1+X2) where B is a matrix, and A, X1, and X2 are vectors. I can't divide by a matrix. So I believe I take the inverse. Is that right? What is the best way of doing this with very large matrices?
  1 commentaire
Matt J
Matt J le 16 Mai 2023
We would have to know what "very large" means to you.

Connectez-vous pour commenter.

Connectez-vous pour répondre à cette question.

Réponse acceptée

Matt J
Matt J le 16 Mai 2023
Modifié(e) : Matt J le 16 Mai 2023
Ran in:
%Fake input data
B=rand(100); X1=rand(100,1); X2=rand(100,1);
A=B*(X1+X2);
%Now invert
X2_recovered=B\(A-B*X1);
norm(X2-X2_recovered) %Check discrepancy - should be small
ans = 4.4786e-13

Plus de réponses (0)

Catégories

En savoir plus sur Mathematics dans Help Center et File Exchange

Tags

Produits


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by