I need to convert a number into its column name equivalent

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Praveen Choudhury
Praveen Choudhury le 15 Oct 2015
Déplacé(e) : Stephen23 le 25 Fév 2025
I'm working on a script that generate some Excel documents and I need to convert a number into its column name equivalent. For example: 1 => A 2 => B 27 => AA 28 => AB 14558 => UMX
  1 commentaire
Stephen23
Stephen23 le 18 Mai 2022
Modifié(e) : Stephen23 le 11 Oct 2023
I was curious about the systematic bugs in the algorithms, which several functions shown on this page demonstrate (producing either errors or incorrect output for some specific letters). So I wrote this simple test function (attached) for checking any such conversion function. It checks all 16384 columns supported by Excel 2007 and later. Note that for simplicity's sake, it does not handle row numbers, so please first modify your function to return the column letters only.
Enjoy!

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Réponses (5)

Praveen Bulusu
Praveen Bulusu le 22 Fév 2020
You can use the following functions. It works for any number.
num=14558
a=num2xlcol(num) % convert number to xlcol
b=xlcol2num(a) % convert xlcol to num
function xlcol_addr=num2xlcol(col_num)
% col_num - positive integer greater than zero
n=1;
while col_num>26*(26^n-1)/25
n=n+1;
end
base_26=zeros(1,n);
tmp_var=-1+col_num-26*(26^(n-1)-1)/25;
for k=1:n
divisor=26^(n-k);
remainder=mod(tmp_var,divisor);
base_26(k)=65+(tmp_var-remainder)/divisor;
tmp_var=remainder;
end
xlcol_addr=char(base_26); % Character vector of xlcol address
end
function xlcol_num=xlcol2num(xlcol_addr)
% xlcol_addr - upper case character
if ischar(xlcol_addr) && ~any(~isstrprop(xlcol_addr,"upper"))
xlcol_num=0;
n=length(xlcol_addr);
for k=1:n
xlcol_num=xlcol_num+(double(xlcol_addr(k)-64))*26^(n-k);
end
else
error('not a valid character')
end
end
  2 commentaires
John McDowell
John McDowell le 6 Juil 2020
Modifié(e) : John McDowell le 6 Juil 2020
These are both really useful functions! Thanks for sharing them
Frederico Pratas
Frederico Pratas le 1 Avr 2021
This is useful, adding some generality to it:
function xlcol_num = xlcol2num(xlcol_addr)
if ischar(xlcol_addr)
xlcol_addr = upper(xlcol_addr);
xlcol_num=0;
n=length(xlcol_addr);
for k=1:n
xlcol_num = xlcol_num + (double(xlcol_addr(k))-double('A')+1)*(length('A':'Z')^(n-k))
end
else
error('not a valid character')
end
end

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Stephen23
Stephen23 le 10 Déc 2019
Modifié(e) : Stephen23 le 15 Juin 2022
Unfortunately Andrei Bobrov's answer does not really take into account the missing zeros, which means that it leads to a kind of "off by one" bug.
Here is an alternative approach which tests correctly on all columns currently supported by Excel (A-XFD) and is limited only by floating point precision (i.e. practically unlimited columns):
d = [1, 2, 26, 27, 28, 702, 703, 704, 14558, 16384]; % A,B,Z,AA,AB,ZZ,AAA,AAB,UMX,XFD
s = arrayfun(@int2xlcol,d)
s = 1×10 string array
"A" "B" "Z" "AA" "AB" "ZZ" "AAA" "AAB" "UMX" "XFD"
function str = int2xlcol(num)
raw = 'A':'Z';
str = raw(1+rem(num-1,26));
tmp = fix((num-1)/26);
while any(tmp)
str = [raw(1+rem(tmp-1,26)),str]; %#ok<AGROW>
tmp = fix((tmp-1)/26);
end
str = string(str);
end
You can also find several submissions on FEX which claim to make this conversion, e.g.:
  1 commentaire
Stephen23
Stephen23 le 15 Juin 2022
Modifié(e) : Stephen23 le 15 Juin 2022
The same approach can also convert multiple values at once:
d = [1, 2, 26, 27, 28, 702, 703, 704, 14558, 16384]; % A,B,Z,AA,AB,ZZ,AAA,AAB,UMX,XFD
z = reshape('A':'Z',[],1);
c = num2cell(z(1+rem(d-1,26)));
v = fix((d-1)/26);
while any(v)
x = v>0;
c(x) = strcat(z(1+rem(v(x)-1,26)),c(x));
v = fix((v-1)/26);
end
s = string(c)
s = 10×1 string array
"A" "B" "Z" "AA" "AB" "ZZ" "AAA" "AAB" "UMX" "XFD"

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Andrei Bobrov
Andrei Bobrov le 15 Oct 2015
Modifié(e) : Andrei Bobrov le 16 Oct 2015
z = 'A':'Z';
d = [1, 2, 27, 28, 14558];
ll = ceil(log(max(d(:)))/log(26));
bs = rem(floor(d(:)*26.^(1-ll:0)),26);
out = cellfun(@(x)z(x(x > 0)),num2cell(bs,2),'un',0);
or
out = arrayfun(@(x)z(rem(floor(x*26.^(1-floor(log(x)/log(26)+1):0)),26)),d(:),'un',0);
  8 commentaires
Andrei Bobrov
Andrei Bobrov le 22 Nov 2020
Modifié(e) : Andrei Bobrov le 22 Nov 2020
function ch = Int2lat(d)
function ch = finner(d)
ll = floor(log(max(d(:)))/log(26))+1;
out = rem(floor(d(:)*26.^(1-ll:0)),26);
lo = ~out;
while any(lo)
out = out + lo*26 - circshift(lo,-1);
out = out(cumsum(out,2) > 0);
lo = ~out;
end
abc = 'A':'Z';
ch = abc(out);
end
ch = arrayfun(@finner,d,'un',0);
end
>> h = Int2lat((1:20)'*26)
h =
20×1 cell array
{'Z' }
{'AZ'}
{'BZ'}
{'CZ'}
{'DZ'}
{'EZ'}
{'FZ'}
{'GZ'}
{'HZ'}
{'IZ'}
{'JZ'}
{'KZ'}
{'LZ'}
{'MZ'}
{'NZ'}
{'OZ'}
{'PZ'}
{'QZ'}
{'RZ'}
{'SZ'}
>>
Stephen23
Stephen23 le 18 Mai 2022
Modifié(e) : Stephen23 le 15 Juin 2022
@Andrei Bobrov: note that function FINNER() returns incorrect 'Z' outputs on MATLAB versions R2016a and earlier, due to the change in the default behavior of CIRCSHIFT's 2nd input argument. For example:
>> finner(26)
ans =
AY

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Remco Hamoen
Remco Hamoen le 19 Avr 2020
Déplacé(e) : Stephen23 le 25 Fév 2025
This function might belp. It converts row and column to 'A1' combinations:
function CELL = xlRC2A1(ROW,COL)
%% Returns the column characters of Excel given a certain column number
% Input COL : number of column
% Output CHAR : Character combination in Excel
if COL <= 26 % [A..Z]
CHAR = char(mod(COL-1,26)+1+64);
CELL = [CHAR num2str(ROW)];
elseif COL <= 702 % [AA..ZZ]
COL = COL-26;
CHAR1 = char(floor((COL-1)/26)+1+64);
CHAR0 = char(mod(COL-1,26)+1+64);
CHAR = [CHAR1 CHAR0];
CELL = [CHAR num2str(ROW)];
elseif COL <= 16384 % [AAA..XFD]
COL = COL-702;
CHAR2 = char(floor((COL-1)/676)+1+64);
COL=COL-(floor((COL-1)/676))*676;
CHAR1 = char(floor((COL-1)/26)+1+64);
CHAR0 = char(mod(COL-1,26)+1+64);
CHAR = [CHAR2 CHAR1 CHAR0];
CELL = [CHAR num2str(ROW)];
else
disp('Column does not exist in Excel!');
end
end
Regards,
Remco

Xavier
Xavier le 25 Fév 2025
Déplacé(e) : Stephen23 le 25 Fév 2025
Very good question ...
This should work whatever what ...
Xavier

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