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fert
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Limit of a Cell

Asked by fert
on 27 Feb 2016
Latest activity Commented on by fert
on 28 Feb 2016
I have a "x1c" cell, and with the following code:
tn=1
for N=1:6591
for t=1:200
k=(((abs(x1c{t,1}(N)-x1c{1,1}(N))).^2))/(6591*200*6)
tn=tn+1;
end
end
I would like to take the "limit of the "k" while t goes infinity"; is it possible?

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1 Answer

Answer by Image Analyst
on 27 Feb 2016
 Accepted Answer

No because you have x1c{t,1} and if t is infinite, then you'd need infinite number of cells in your cell array, which you don't have enough memory for.

  18 Comments

fert
on 28 Feb 2016
I couldn't make smaller the file for 5 Mb, thus I uploaded here:
Perhaps I'll try something later if you you answer my two questions in my earlier reply (third and last chance or I'm moving on).
fert
on 28 Feb 2016
Oh I am so sorry.
So, x1c{1} is x1, and x1c{2} is x2, and x1c{3} = x3? Is that correct?
It is not correct. x1c{1} is a cell which includes 6591 atoms' i j k position directions.
Okay, but then why does x1, x2, and x3 have 3 columns instead of 1? According to the formula, x sub n takes one index and a 2D array would take 2 indexes.
Since it contains both i j k directions.

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