Asked by fert
on 27 Feb 2016

I have a "x1c" cell, and with the following code:

tn=1

for N=1:6591

for t=1:200

k=(((abs(x1c{t,1}(N)-x1c{1,1}(N))).^2))/(6591*200*6)

tn=tn+1;

end

end

I would like to take the "limit of the "k" while t goes infinity"; is it possible?

Answer by Image Analyst
on 27 Feb 2016

Accepted Answer

fert
on 28 Feb 2016

I couldn't make smaller the file for 5 Mb, thus I uploaded here:

Image Analyst
on 28 Feb 2016

fert
on 28 Feb 2016

Oh I am so sorry.

So, x1c{1} is x1, and x1c{2} is x2, and x1c{3} = x3? Is that correct?

It is not correct. x1c{1} is a cell which includes 6591 atoms' i j k position directions.

Okay, but then why does x1, x2, and x3 have 3 columns instead of 1? According to the formula, x sub n takes one index and a 2D array would take 2 indexes.

Since it contains both i j k directions.

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