index out of bounds because numel(uold)=1 Error
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Ishfaq Ahmad Bhat
le 23 Nov 2016
Commenté : Ishfaq Ahmad Bhat
le 23 Nov 2016
Please help in removing the error in matlab code. I tried with changing the variable but that didn't help.
% Defining constants;
L=10; % length of domain in x-direction
tmax=10; % end time
nx=50; % number of nodes in x-direction
nt=50; % number of time steps
dx=L/(nx-1); % Length of space interval
dt=tmax/(nt-1); % Length of time interval
alpha=input('Enter the value of alpha: ');
r=alpha*dt/dx^2;
r2=1-2*r;
% INITIAL CONDITION
t=0;
u=0;
% LOOP OVER TIME STEPS
for m=1:nt
uold=u;
t=t+dt;
% LOOP OVER SPACE STEPS
for i=2:nx-1
u(i)=r*uold(i-1)+r2*uold(i)+r*uold(i+1);
end
end
1 commentaire
KSSV
le 23 Nov 2016
YOur code will work only when u is made a vector. At present u is only scalar equals to 0.
Réponse acceptée
Preethi
le 23 Nov 2016
hi,
initialize u with a vector of zeros instead of '0'. for ex
u =zeros(1,nx-1)
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Matrices and Arrays dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!