Add newer data to older data without repetition
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Martin
le 17 Fév 2018
Réponse apportée : Peter Perkins
le 17 Fév 2018
Imagine 2 two datasets where column 1 is a timestamp, column 2 is data (can be more columns).
Yesterday i had this:
A = [ 1 2 3 4 5 6 7 ; 435 124 525 342 532 533 213 ]'
Today I get this (Rows each day can vary):
B = [ 5 6 7 8 9 10 ; 532 533 213 988 999 777 ]'
So 5:7 (timestamp) overlaps. Any idea how I can end up connecting those time stamps so I can get this:
C= [ 1 2 3 4 5 6 7 8 9 10 ; 435 124 525 342 532 533 213 988 999 777]'
I want to return all the data in A and B without repeating the data common to both A and B (not just simple concatinating)
Thanks in advance
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Peter Perkins
le 17 Fév 2018
If you are using R2016b or later, you may find that using timetables is convenient. For example, union works the same way as what Guillaume showed ...
>> A = timetable(seconds([1 2 3 4 5 6 7]'), [435 124 525 342 532 533 213]')
A =
7×1 timetable
Time Var1
_____ ____
1 sec 435
2 sec 124
3 sec 525
4 sec 342
5 sec 532
6 sec 533
7 sec 213
>> B = timetable(seconds([5 6 7 8 9 10]'),[532 533 213 988 999 777]')
B =
6×1 timetable
Time Var1
______ ____
5 sec 532
6 sec 533
7 sec 213
8 sec 988
9 sec 999
10 sec 777
>> union(A,B)
ans =
10×1 timetable
Time Var1
______ ____
1 sec 435
2 sec 124
3 sec 525
4 sec 342
5 sec 532
6 sec 533
7 sec 213
8 sec 988
9 sec 999
10 sec 777
but timetables also bring along a lot of other functionality around "combining data".
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