could anyone help me to solve this issue.

I am getting the result in the following manner

iwant =
  34    12
  24    13
  23    14

if i use the command line

sprintf('%d',iwant) - '0'

i am getting

ans =
   3     4     2     4     2     3     1     2     1     3     1     4

But i want to have the result in the following way

(3 4 1 2,2 4 1 3, 2 4 1 4)

Could anyone help me to fix this issue.

[Akira Agata]

Question for clarification.

You want to convert the following numeric 1-by-6 array into the string ('3 4 1 2,2 4 1 3, 2 4 1 4') ?

iwant = [34 12 24 13 23 14];

[Prabha Kumaresan]

i want to separate 3 and 4, 1 and 2, 2 and 4 and so on. But how it can be implemented for n numbers.

Answer 1

[Akira Agata]

Like this?

iwant = [34 12 24 13 23 14];
c = num2cell(erase(num2str(iwant),' '));
output = str2double(c);

In this case, the output is the following 1-by-12 numeric vector.

>> output
output =
   3     4     1     2     2     4     1     3     2     3     1     4

[Prabha Kumaresan]

but when i run the code i am getting errror Undefined function or variable 'erase'. Error in line c = num2cell(erase(num2str(iwant),' '))

[Walter Roberson]

erase() requires R2016b or later.

... It would be easier to assist you if you upgraded to a recent MATLAB version.

Answer 2

[Walter Roberson]

 cell2mat(cellfun(@(C) C-'0', sprintfc('%d', iwant), 'uniform', 0))

This does assume that the entries all have the same number of digits (but does not assume that the number of digits is 2)

[Prabha Kumaresan]

As i am getting error I am unable to use cell2mat(cellfun(@(C) C-'0', sprintfc('%d', iwant), 'uniform', 0))

[Walter Roberson]

What error are you encountering? And could you remind me which version you are using?

[Prabha Kumaresan]

i am using 2015b.

if i run the code:

iwant = [34 12 24 13 23 14]
c = num2cell(erase(num2str(iwant),' '))
output = str2double(c)
sprintf('%d',iwant) - '0'
cell2mat(cellfun(@(C) C-'0', sprintfc('%d', iwant), 'uniform', 0))

I am getting Undefined function or variable 'erase'.

[Stephen23]

@Prabha Kumaresan: Did you read this from three hours ago?:

https://www.mathworks.com/matlabcentral/answers/390653-could-anyone-help-me-to-solve-this-issue#comment_549544

[Walter Roberson]

MATLAB R2015b:

>> iwant = [ 34    12
  24    13
  23    14]

iwant =

      34    12
      24    13
      23    14

>>  cell2mat(cellfun(@(C) C-'0', sprintfc('%d', iwant), 'uniform', 0))

ans =

       3     4     1     2
       2     4     1     3
       2     3     1     4

Please post a complete copy of the error message you encounter when you run the code that I posted. Not someone else's code: you said that you encountered an error running my code.

Answer 3

[Jan]

The best idea would be to create the numbers in the correct format directly. I guess, that you used a method I have suggested to one of your former questions, where it was not clear if you want "3, 4" or "34". If this is the case, simply omit the multiplication by [10; 1].

But to solve the current problem:

iwant = [34 12; 24 13; 23 14];

b = rem(iwant(:).', 10);
a = (iwant(:).' - b) / 10;
reshape(permute(reshape([a,b], [3,2,2]), [1,3,2]), 3,4)

     [3     4     1     2; ...
      2     4     1     3; ...
      2     3     1     4];

Please note, that "(3 4 1 2,2 4 1 3, 2 4 1 4)" is not clear, because it is not a valid Matlab syntax.