Integrate with Simpson's Rule
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Danny Helwegen
le 13 Jan 2019
Modifié(e) : David Goodmanson
le 14 Jan 2019
Hi i have, probably an easy, problem. I made a function (see the outcome below) and i need to integrate the outcome, but since the interval is small the subscript indices aren't integers. This is the problem:
f =
0.0028 0.1333 0.2667 0.4000 0.5333 0.6667 0.8000 0.9333 1.0667 1.1972
So then i use the Simpson Rule:
%interval is [0,1.2]
a = 0; b = 1.2; n =10; h = (b-a)/n
xi=a:h:b
I = h/3*(f(xi(1))+2*sum(f(xi(3:2:end-2)))+4*sum(f(xi(2:2:end)))+f(xi(end)));
But i get the error: Subscript indices must either be real positive integers or logicals.
How can I solve this?
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Matt J
le 14 Jan 2019
Modifié(e) : Matt J
le 14 Jan 2019
It doesn't look like you xi should be involved, since you already have the samples of f
I = h/3*(f((1))+2*sum(f((3:2:end-2)))+4*sum(f((2:2:end)))+f((end)));
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David Goodmanson
le 14 Jan 2019
Modifié(e) : David Goodmanson
le 14 Jan 2019
Addressing f_i directly (assuming the x_i are equally spaced) is the right method, but the problem is that f has an even number of points. So the end point f(10) gets a weight of 5, not 1.
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