I am working on Imdian currency recognition and developed the code for same but some errors are troubling me. Please check.
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
deepika
le 28 Mar 2019
Réponse apportée : Walter Roberson
le 28 Mar 2019
clear all;
close all;
clc;
vid=videoinput('winvideo',1,'YUY2_320x240');
set(vid,'FramesPerTrigger',Inf);
set(vid,'returnedColorspace','rgb');
vid.FrameGrabInterval=5;
start(vid);
while(vid.FramesAcquired<=10)
data=getsnapshot(vid);
% image(data)
end
stop(vid);
image(data);
h = imrect;
pos = getPosition(h);
strip11=imcrop(data,pos);
figure;
imshow(strip11);
%imwrite(strip11,'k2000.jpg');
im1=imread('note2000.jpg');
im1=imresize(im1,[200,600]);
%[m,n,l]=size(im1);
figure;
subplot(2,2,1);
imshow(im1);
a=kavi_feature(im1);
%im2=imread('note500.jpg');
im=imresize(strip11,[200,600]);
%[m,n,l]=size(im1);
figure;subplot(2,2,1);imshow(im);
b=kavi_feature(im);
d=dist(a,b');
if(d<40743.1616752612)
disp('note is same')
else
disp('note is different');
end
function final_out = kavi_feature(im)
[m,n,l]=size(im);
a=double(im)/255;
R=a(:,:,1);
G=a(:,:,2);
B=a(:,:,3);
num=(1/2)*((R-G)+(R-B));
denom=((R-G).^2+((R-B).*(G-B))).^0.5;
H=acos(num./denom);
H(B>G)=360-H(B>G);
H=H./360;
%subplot(2,2,2);imshow(h);
S=1-(3.*min(a,[],3));
%subplot(2,2,3);imshow(s);
I=(R+G+B)/3.255;
%subplot(2,2,4);imshow(i);
HSI(1:m,1:n,1:l)=0;
HSI(:,:,1)=H(:,:);
HSI(:,:,2)=S(:,:);
HSI(:,:,3)=I(:,:);
h=HSI(:,:,1);
s=HSI(:,:,2);
i=HSI(:,:,3);
subplot(2,2,2);h3=imhist(h);
subplot(2,2,3);imhist(s);
subplot(2,2,4);imhist(i);
y=mean(a(:));
y1 = var(a(:));
y2 = std(a(:)) ;
A=[h3' y y1 y2];
C1 = colorAutoCorrelogram(im);
h1 = hsvHistogram(im);
w = waveletTransform(im);
final_out=[A,C1,h1,w];
End
1 commentaire
Réponse acceptée
Walter Roberson
le 28 Mar 2019
https://www.mathworks.com/matlabcentral/fileexchange/42008-content-based-image-retrieval defines colorAutoCorrelogram.
0 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Data Import and Analysis dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!