Could anyone help me how to solve the issue.

how to add all the values generated using for loop

for example

A=[1 2],[3 4],[7 5 6]

for i=1:length(A)

value% i am using formula to calculate the value

end

In this code first it run for [1 2] generates a value-(a)

then it run for [3] generates a value-(b)

then it run for [4 5 6] and generates a value-(c)

Now i want to add (a)+(b)+(c) after the end statement so i tried with the follwing command sum(value,:) but unable to get the result.

Could anyone please help me on this.

Answer 1

[Stephen23]

Using very basic MATLAB indexing:

A = {[1,2],[3,4],[7,5,6]};
N = numel(A);
Z = nan(1,N);
for k = 1:N
    Z(k) ... your code using A{k}
end
sum(Z)

@ jaah navi: you have been using MATLAB since 2017, loops and indexing are very basic programming concepts that you should definitely learn yourself, they are explained in the introductory tutorials:

https://www.mathworks.com/help/matlab/getting-started-with-matlab.html

https://www.mathworks.com/help/matlab/matlab_prog/preallocating-arrays.html

[jaah navi]

i tried but unable to get the result.

in my code

length = 1:5

for

need to take 1st length and compute value-(a)

.. -(b)

.. -(c)

.. -(d)

need to take 5th length and compute value-(e)

end

now i need to add all the values together which means a+b+c+d+e

when i used the command sum(value),it displays the last value e without adding a+b+c+d+e together.Could you please help me on this.

[jaah navi]

with respect to your sample code

A = {[1,2],[3,4],[7,5,6]};

N = numel(A);

Z = nan(1,N);

for k = 1:N

Z(k) ... your code using A{k}

end

sum(Z)

The code is for A={[1,2],[3,4],[7,5,6]};

in the same manner i have different numbers for A

for example

when

A = {[1,2],[3,4],[7,5,6]};

the output can be obtained by sum(Z)

when A={[4 5 ],[1 3 4]

i can get the output by sum(Z)

now i need to add both sum(Z)

could you please help me on this.

[Stephen23]

jaah navi : you wrote in your original question that you have some code that "generates a value-(a)" and "generates a value-(b)" and "generates a value-(c)". You did not show us what that code is, or explain anything about how it works. However you made it clear that it returns a scalar "value". All you need to do is use indexing to put that scalar value into the numeric array Z, exactly as my answer shows you. The cell array A is irrelevant to this: my code uses numel to adjust to whatever size A happens to be.

If your code does not actually return a scalar value then you need to revise your question and explain the your data much better.