- You set options for fsolve, but then call lsqnonlin. This is a mistake.
- You do not pass options to the solver. This might be a mistake.
- You have six equations in four unknowns. Generally, you should not expect a solution to such a system, only a point that is a local minimum of the sum of squares.
How to solve 4 equations with 4 unknowns with bounds?
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Hi everyone, I'm trying to solve this but the message displayed local minimum found and also the values of the x generated did not match with the boundary which was set ie. x(1)+x(2) = Ym. It also says lsqnonlin stopped because the final change in the sum of squares relative to its initial value is less than the value of the function tolerance.Could anyone help with this? Many thanks!
clear; clc;
x0 = [50; 50; 50; 50;];
options = optimoptions('fsolve','Display','iter');
%[x,fval] = fsolve(@myfun,x0,options)
lb = [0; 0; 0; 0;];
ub = [100; 100; 100; 100;];
x = lsqnonlin(@myfun,x0,lb,ub)
myfun(x)
function F = myfun(x)
A = 87.3145;
B = -0.289762;
C = 0.0000199677;
alpha = 0.4705;
Xm = 20;
Ym = 27.5;
F = [x(1)+x(2)-Ym;
x(3)+x(4)-Xm;
A*exp(B*x(3)^0.5 - C*x(3)^3) - x(1);
A*exp(B*x(4)^0.5 - C*x(4)^3) - x(2);
Ym/alpha - ((1-alpha)/alpha)*x(2) - x(1);
Xm/alpha - ((1-alpha)/alpha)*x(4) - x(3);
]
end
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Réponse acceptée
Alan Weiss
le 22 Avr 2019
Alan Weiss
MATLAB mathematical toolbox documentation
Plus de réponses (1)
Alex Sha
le 16 Mai 2019
Refer the results below:
x1: 7.73410323214524
x2: 32.0801819920043
x3: 33.4573119565274
x4: 11.2688338748665
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