Can I arrange a double array into cell array based on discontinuity of values?
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I have 1x15 double array defined as 'a' and I would like to make them classified into each cell column if the increment of value is broken. This is my code, I have no idea how to make a1 become a2. If the next value is not the prvious number, n+1, then it should break and create new cell column.
axis([0 30 0 30]);
hold on;
a1=[1 2 3 4 5 10 11 12 13 18 19 20 21 22 23];
a2={[1 2 3 4 5] [10 11 12 13] [18 19 20 21 22 23]} ;
cellfun(@(x) plot(x,x), a2);
The length is not fixed, it could be like this
a1=[1 2 3 4 5 6 7 8 9 10 11 12 13 18 19 20 21 22 23];
a2={[1 2 3 4 5 6 7 8 9 10 11 12 13] [18 19 20 21 22 23]} ;
or like this.
a1=[1 2 3 4 11 12 13 18 19 20 21 22 23 30 31 32 33 40 41 42];
a2={[1 2 3 4] [11 12 13] [18 19 20 21 22 23] [30 31 32 33] [40 41 42]};
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Voss
le 14 Déc 2023
a1=[1 2 3 4 5 10 11 12 13 18 19 20 21 22 23];
a2 = split_vector(a1)
a1=[1 2 3 4 5 6 7 8 9 10 11 12 13 18 19 20 21 22 23];
a2 = split_vector(a1)
a1=[1 2 3 4 11 12 13 18 19 20 21 22 23 30 31 32 33 40 41 42];
a2 = split_vector(a1)
function out = split_vector(a)
d = diff(a);
n = diff(find([true, d>min(d), true]));
out = mat2cell(a,1,n);
end
1 commentaire
Dyuman Joshi
le 14 Déc 2023
Another method -
a1=[1 2 3 4 5 10 11 12 13 18 19 20 21 22 23];
a2 = split_vector(a1)
a1=[1 2 3 4 5 6 7 8 9 10 11 12 13 18 19 20 21 22 23];
a2 = split_vector(a1)
a1=[1 2 3 4 11 12 13 18 19 20 21 22 23 30 31 32 33 40 41 42];
a2 = split_vector(a1)
function out = split_vector(a)
idx = [find(diff(a)~=1) numel(a)];
out = mat2cell(a, 1, [idx(1) diff(idx)]);
end
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