How to find position of array
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Wind flower
le 17 Juin 2019
Modifié(e) : madhan ravi
le 20 Juin 2019
For example i have data like this [11111100001111]
Now i need to find out the position of first 1 and last 1 of first group of 1s and then position of first 1 and last 1 of second group of 1s. How do i do this??
i have used' find' to find the position of all 1s but i dont want all...instead 1 want only the first and last position of groupof 1s
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Debasish Samal
le 17 Juin 2019
Modifié(e) : Debasish Samal
le 17 Juin 2019
You can use regular expressions to do this.
x = '11111100001111';
expr = '1*';
[sInd,eInd] = regexp(x, expr)
This gives the following result:
sInd = 1×2
1 11
eInd = 1×2
6 14
You just need to convert the input data into a string.
6 commentaires
Debasish Samal
le 20 Juin 2019
Modifié(e) : Debasish Samal
le 20 Juin 2019
@Wind flower as far as I know xlsread returns a matrix of integers(if you are reading integers). So very basic approach would be using num2str to convert the num type to string type. Then iterate over each cell to get the result. I am not sure how your data looks like after reading it using xlsread. But I am sure you can figure out a way to optimise the conversion and get the desired result. Thanks.
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madhan ravi
le 17 Juin 2019
Simpler without any conversions:
s=[1 0 1 1 0 0 0 0 1 1 1 1]; % example data
x=s~=0;
Start = strfind([0,x],[0 1])
End = strfind([x,0],[1 0])
3 commentaires
Rik
le 17 Juin 2019
Note that using numeric arrays as inputs to strfind is currently undocumented (and it even returns an error in GNU Octave). It would be nice if Mathworks changed the documentation. It would be even better if they extended this function to work on arrays of any object type.
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