How can I assign several values from cell-array tovariables?

Asked by Diego R on 4 Sep 2019

Latest activity Answered by Diego R on 5 Sep 2019

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I have the cell array from the example:

myNum = [1, 2, 3]; myCell = {'one', 'two'}; myStruct.Field1 = ones(3); myStruct.Field2 = 5*ones(5);
C = {myNum, 100*myNum;      myCell, myStruct}

C = 2x2 cell array

{1x3 double} {1x3 double}

{1x2 cell } {1x1 struct}

I want to receive:

a=1

b=2

c=3

I've tried to do these, but didn't work:

[a,b,c]=C{1,1}
[a,b,c]=deal(C{1,1}(1,:))

I need to do in one time because my real code has dozens of values.

Thanks in advance for answers.

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3 Answers

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Answer by Kelly Kearney on 4 Sep 2019

Accepted Answer

I think you'll need to use a quick intermediate variable so you can convert the numeric array to a comma-separated list:

tmp = num2cell(C{1,1});
[a,b,c] = deal(tmp{:})

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Star Strider on 5 Sep 2019

In more recent MATLAB releases, deal isn’t necessary.

Just use:

[a,b,c] = tmp{:}

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Answer by Walter Roberson on 5 Sep 2019

Unfortunately the temporary variable is still a practical necessity. It can be done away with, at cost:

[a,b,c] = subsref(num2cell(C{1,1}), struct('type', '{}', 'subs', {{':'}}))

but it becomes a lot easier if you define

VECEXPAND = @(VEC) VEC{:};
DEALVEC = @(VEC) VECEXPAND(num2cell(VEC));
[a, b, c] = DEALVEC(C{1,1})

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Answer by Diego R on 5 Sep 2019

Thanks a lot. It works. But it is a shame there isn't a direct way.

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