remove repeated rows to produce two new matrices

Hi everyone, I have 2 matrices, A and B. As you can see, everyrow in A is for a particular row in B. What I want to to do is for a repetitive, I want to remove them and take the highest value in A. For example, 3 to 10 appears twice (3 4 5 7 8 10 & 3 4 5 6 9 8 10 with corresponding A values of 0.213157025 and 0.207067988 respectively). From this two, I would take 0.213157025 because its higher. I then produce C and D accordingly by producing C in terms of putting the first and last number in each row with their corresponding A values in D.

a = [0.359883241
0.277815278
0.247562838
0.26249033
0.226989582
0.213157025
0.207067988
0.204762201
];

b =[3	  4	0	0	0	0	0
3	4	5	0	0	0	0
3	4	5	7	6	0	0
3	4	5	7	0	0	0
3	4	5	7	8	0	0
3	4	5	7	8	10	0
3	4	5	6	9	8	10
3	4	5	7	8	10	11
];

I would like to produce C and D

C =[3 4
    3 5
    3 6
    3 7
    3 8 
    3 10
    3 11]

D = [0.359883241
0.277815278
0.247562838
0.26249033
0.226989582
0.213157025
0.204762201
];

Answer 1

[Adam Danz]

% Convert b to [first,last] non-zero per row
b2 = splitapply(@(x)x([find(x~=0,1,'first'),find(x~=0,1,'last')]),b,(1:size(b,1)).'); 

% Get unique rows of b2
[C, Cidx] = unique(b2,'rows');

% Get the corresponding 'a' values
D = a(Cidx); 

Answer 2

[Stephen23]

An old-fashioned way:

a = [0.359883241;0.277815278;0.247562838;0.26249033;0.226989582;0.213157025;0.207067988;0.204762201]
b = [3,4,0,0,0,0,0;3,4,5,0,0,0,0;3,4,5,7,6,0,0;3,4,5,7,0,0,0;3,4,5,7,8,0,0;3,4,5,7,8,10,0;3,4,5,6,9,8,10;3,4,5,7,8,10,11]
% Indices of last non-zero:
tmp = b.';
tmp(end+1,:) = 0;
idx = 1==diff(cumprod(tmp,1)==0);
idx(end+1,:) = false;
% 
[T,X] = sortrows([b(:,1),tmp(idx),a]);
[C,Y] = unique(T(:,1:2),'rows','last');
D = a(X(Y));

Giving:

>> C
C =
    3    4
    3    5
    3    6
    3    7
    3    8
    3   10
    3   11
>> D
D =
   0.35988
   0.27782
   0.24756
   0.26249
   0.22699
   0.21316
   0.20476