Cycle counting from 0
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I have a matrix [ 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0] for exemple
I'd like to have an outing:
2 x 4 "0" in succession
2 x 2 "0" in succession
1 x 3 "0" in succession
How to program it
Thank you.
2 commentaires
Image Analyst
le 11 Déc 2019
Modifié(e) : Image Analyst
le 11 Déc 2019
I have no idea what you want. What is an "outing"? Do you mean output? If so, what is the output array you want? I can't tell from your word descriptions. Type it out in numbers like you did for the input matrix.
Stephen23
le 12 Déc 2019
stefan's "Answer" moved here:
With this matrix : [ 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0 1 1 1 1 1 0 0 0 0 0 ]
I would have liked to have this matrix :
|5 2|
|6 1|
|4 1|
With the 1st column the number of successive 0
With the 2nd column the number of the sequence
thanks
Réponse acceptée
Stephen23
le 12 Déc 2019
Modifié(e) : Stephen23
le 12 Déc 2019
>> M = [0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,1,1,1,0,0,0,0,1,1,1,1,1,0,0,0,0,0];
>> D = diff([false;M(:)==0;false]);
>> L = find(D<0) - find(D>0);
>> [U,~,X] = unique(L,'stable');
>> V = histc(X,1:max(X));
>> Z = [U(:),V(:)]
Z =
5 2
6 1
4 1
7 commentaires
Stephen23
le 14 Déc 2019
Modifié(e) : Stephen23
le 14 Déc 2019
"I have a vector that can have values from 1 to 15. I would like to know the number of times for all the possible changes: for example:"
from 1 to 2
from 2 to 11
from 14 to 3
....
None of your provided data includes the values 11 or 14, so you are asking me to help you on an unknown algorithm with unknown data. Sorry, but my magic crystal ball is not working today.
"from 2 to 3 and from 3 to 4, I don't have the couples (1,2) and (2,3)."
Well, that makes two of us, because I don't have them either! Nor do you explain what they are, or how they relate to 1, 2, 11, 14, and 3 from your previous comment, or the binary data of your original question.
One clear explanation of the method/algorithm (complete with input and output example data) would actually mean that you get the help that you are looking.
Plus de réponses (1)
Akira Agata
le 12 Déc 2019
How about the following?
x = [0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0 1 1 1 1 1 0 0 0 0 0];
str = num2str(x')';
c = regexp(str,'0+','match');
len = cellfun(@numel,c);
output = [(1:max(len))', accumarray(len',1)];
The result becomes like this:
>> output
output =
1 0
2 0
3 0
4 1
5 2
6 1
2 commentaires
Akira Agata
le 12 Déc 2019
You mean, the order is also important?
My output is same as what you expected, except the order of rows and including 0 sequence cases (such as 1~3 consecutive zeros).
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