How to sort a structure by numbers in one of its fields?

13 vues (au cours des 30 derniers jours)
Scott Rauscher
Scott Rauscher le 31 Oct 2012
First of all, I have used a workaround to label my structure fields as distances as the following:
RX.(['d',num2str(distance{1})])(:,1) = data(:,45); % COTS 1, X-axis
RX.(['d',num2str(distance{1})])(:,2) = data(:,46); % COTS 1, Y-axis
etc.
so that my structure in the end looks like this:
d0: [600000x6 double]
d100: [525000x6 double]
d10: [550000x6 double]
d20: [475000x6 double]
d2: [550000x6 double]
d30: [450000x6 double]
d40: [525000x6 double]
d4: [600000x6 double]
d50: [525000x6 double]
etc.
I would like to be able to sort the fields in the structure so that they'd end up as
d0: [600000x6 double]
d2: [550000x6 double]
d4: [600000x6 double]
d6: [600000x6 double]
d8: [600000x6 double]
d10: [600000x6 double]
d20: [600000x6 double]
etc.
I can get as far as
RXnames = fieldnames(RX);
for j = 1:length(RXnames)
RXd(j) = regexpi(RXnames{j},'d(\d\d*)','tokens');
RXd(j) = RXd{j};
end
RXd = RXd';
which gives me the distances in a string array:
'0'
'100'
'10'
'20'
'2'
'30'
'40'
'4'
'50'
'60'
'6'
'70'
'80'
'8'
'90'
and then I can str2double them to a number array which I can then sort, but then I lose association with the fields. Does anyone know of a way to sort the way I'm describing?
Thanks to anyone in advance!
Scott

Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 31 Oct 2012
eg
a = struct('d100',randi(125,4,5),'d458',3,'d7',rand(3),'d0','sd456'); % your data
p1 = regexp(fieldnames(a),'\d*','match');
[i1,i1] = sort(str2double(cat(1,p1{:})));
out = orderfields(a,i1)
  1 commentaire
Scott Rauscher
Scott Rauscher le 1 Nov 2012
Ah, perfect. There's some smart people on here...
Thank you

Connectez-vous pour commenter.

Plus de réponses (2)

Azzi Abdelmalek
Azzi Abdelmalek le 31 Oct 2012
Modifié(e) : Azzi Abdelmalek le 31 Oct 2012
s=fieldnames(x)
c=char(s)
s1=cellfun(@(x) (regexp(x,'\d+','match')),s,'un',0)
s2=cellfun(@str2double,s1)
[s3,idx]=sort(s2)
for k=1:numel(s2)
b.(['d' num2str(s3(k))])=x.(strtrim(c(idx(k),:)))
end
x=b
  1 commentaire
Scott Rauscher
Scott Rauscher le 1 Nov 2012
Modifié(e) : Scott Rauscher le 1 Nov 2012
This worked perfectly, but the one right above you took less lines of code. Thank you though!!

Connectez-vous pour commenter.


Milos
Milos le 31 Oct 2012
You will have to pad field names with zeros:
d000
d005
d010
d077
d100
and then you can sort the fields using function:
orderfields

Catégories

En savoir plus sur Structures dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by