Finding Prime numbers (NO isprime function)
17 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi, I am trying to return if the value is prime or not. And here is my code
vec = [3 4 88 5 1371];
for i = 1:length(vec)
b = mod(vec(i),2);
if vec(i)==1
disp('not prime');
elseif vec(i)==2
disp('prime');
elseif b==0
disp('not prime');
elseif b>0
for j = 3:2:(vec(i)-1)
b = mod(vec(i), j);
if b==0
disp('not prime');
end
end
disp('prime');
else
disp('not prime');
end
end
However, this code returned this
prime
not prime
not prime
prime
not prime
not prime
prime
Could you please tell me why its returning 7 outputs not 5? Also could you fix this code so it only returns 5 outputs?
2 commentaires
Stephen23
le 13 Juin 2020
Modifié(e) : Stephen23
le 13 Juin 2020
"Could you please tell me why its returning 7 outputs not 5?"
Look at your j-loop: within that loop your code could call disp zero, one, or more times, depending on the vec(j) value.
And then after the j-loop, you call disp once more. Your code does nothing to ensure that you only call disp once for each vec value.
"Also could you fix this code so it only returns 5 outputs?"
Get rid of the j-loop and write vectorized code. It will be simpler.
Note that you do not need to check up to vec(i)-1, up to sqrt(vec(i)) is sufficient and more efficient.
Réponses (1)
Walter Roberson
le 13 Juin 2020
if b==0
disp('not prime');
end
You should exit the j loop as soon as you prove the number is not prime.
disp('prime');
You are doing that no matter what the outcome of your for j loop is.
2 commentaires
Walter Roberson
le 13 Juin 2020
if b==0
disp('not prime');
break;
end
end
if b ~= 0
disp('prime')
end
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!