Is it possible to accelerate the speed of saving data into files with parallel way?

6 vues (au cours des 30 derniers jours)
I am trying to save data to files, i.e. txt file. The speed is very low. This step takes almost 80% time over my whole script. My computer has many cores. Could I use them, i.e. parallel way, to help to accelerate the speed in Matlab? I don't know much about know this. May it is impossible. Please just tell me some idea or suggestion about it? Thank you very much.
(edited as Rik suggested)
My code uses fprintf function in a big loop. This is the most time consuming step.
i.e. I need to save a large matrix a, which is 4000000*4
p = fopen(filename,'w');
for i=1:length(a)
fprintf(fp,'%d %d %d %d\n',a(i,1),a(i,2),a(i,3),a(i,4));
end
Is there any method to accelerate it?
  4 commentaires
Rik
Rik le 19 Juil 2020
Without knowing more about your code, this is only conjecture. You need to post exact code if you want specific advice. You can also run the profiler to find bottlenecks in your code.
wei zhang
wei zhang le 21 Juil 2020
@Rik I had add a mini example of my fprintf codes. I haven't find any method to improve it. Maybe it is impossible.

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Bruno Luong
Bruno Luong le 21 Juil 2020
Modifié(e) : Bruno Luong le 21 Juil 2020
You might try to remove the for-loop
fp = fopen(filename,'w');
fprintf(fp,'%d %d %d %d\n', a(:,1:4).'); % remove the indexing with your array has 4 columns
fclose(fp);
A file is a sequential access device. There is no use of parallel CPU. When you write a file a hard disk head must go sequentially in tracks and put a little electrical signal there to store your data. More or less samething happens with all other HW, even SSD.
Another thing that takes time is convert the internal binary format to digital of your fprintf('%d').
If you can, just write file in binary format. That is the best method (fatest).
  2 commentaires
wei zhang
wei zhang le 21 Juil 2020
I have tested your codethat your way could accelerate the process remarkably. Really thankful. The inputs should be matrix, not number. Could you give another advice to the code below to remove the for loop? I have no ideas about it with only symbol.
for i = 1:n_face
fprintf(fp,'0 0\n');
end
Bruno Luong
Bruno Luong le 21 Juil 2020
Try this:
fp = fopen('test.txt','w')
fwrite(fp, repmat(sprintf('0 0\n'),1,n_face));
fclose(fp);
Or you could do with the same method as I have showed
fp = fopen('test.txt','w');
a = repmat([0 0], n_face, 1);
fprintf(fp,'%d %d\n', a); % no need for transpose since it's all 0s
fclose(fp);

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Plus de réponses (1)

Mohammad Sami
Mohammad Sami le 21 Juil 2020
Modifié(e) : Mohammad Sami le 21 Juil 2020
Is there a reason why you want to use a for loop to write this ?
You can write the entire matrix to file in one go using writematrix function.
a = randi([0 10],1000000,4);
tic;
writematrix(a,'abc.txt','FileType','text','Delimiter',' ');
toc;
  1 commentaire
Rik
Rik le 21 Juil 2020
I'm on mobile so I can't write and test the code, but you can also use fprintf. You just need to make sure the orientation of a is correct (it will read the input column by column when writing the lines in the text file).

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