How to display a particular row of a matrix using loop

x = [0:10:90]*pi/180;

x assumes 10 values.

After some codes, not giving here I have a matrix AR of size 8 x 10 complex double.Here 10 columns in AR correspond to x.

AR looks like this

 Columns 1 through 6

  -0.7907 - 0.0715i  -0.9790 + 0.0019i  -1.0042 + 0.0097i  -0.2129 - 0.0251i   0.2552 + 0.0330i  -1.4969 + 0.0031i
  -2.5799 + 1.6142i   0.2074 - 0.0561i   9.9110 - 0.2609i  -3.5511 - 0.0974i -21.2789 - 0.0706i   1.5682 + 0.0124i
  -5.0430 + 3.5473i  -3.4284 + 0.1915i -11.5629 + 0.3133i   2.1664 + 0.0879i  11.8606 - 0.0985i  -0.0417 - 0.0234i
  -0.0000 - 0.0000i   0.0000 - 0.0000i   0.0000 - 0.0000i   0.0000 + 0.0000i  -0.0000 - 0.0000i   0.0000 - 0.0000i
   0.0184 + 0.0453i   0.1697 - 0.0032i   0.3204 - 0.0054i   0.1289 - 0.0000i   0.3203 - 0.0216i   0.3298 - 0.0100i
  -2.2066 + 1.2603i   0.3310 - 0.0068i  -0.0718 + 0.0024i  -0.0427 - 0.0013i  -0.7890 - 0.1629i   0.1793 - 0.0014i
  -5.2254 + 3.7843i  -3.7008 + 0.1472i  -1.9046 + 0.0651i  -0.6838 - 0.0333i  -7.6944 + 0.0484i   0.5205 + 0.0034i
   0.0000 + 0.0000i  -0.0000 + 0.0000i  -0.0000 + 0.0000i  -0.0000 - 0.0000i   0.0000 + 0.0000i  -0.0000 + 0.0000i

  Columns 7 through 10

   0.0047 + 0.0058i  -0.1811 + 0.0005i   0.4990 + 0.0020i      NaN +    NaNi
   2.6128 + 0.0132i   4.4093 + 0.0143i  12.9729 + 0.1027i      NaN +    NaNi
  -1.8643 - 0.0154i  -2.1497 - 0.0076i  -4.2649 + 0.0165i      NaN +    NaNi
  -0.0000 - 0.0000i   0.0000 - 0.0000i  -0.0000 - 0.0000i      NaN +    NaNi
  -0.3435 - 0.0048i  -1.4333 - 0.0049i  -1.6707 - 0.0107i      NaN +    NaNi
   0.0932 - 0.0007i  -0.0587 - 0.0002i  -0.0572 - 0.0019i      NaN +    NaNi
   2.0034 + 0.0091i   4.5705 + 0.0122i  11.9349 + 0.1339i      NaN +    NaNi
   0.0000 + 0.0000i  -0.0000 + 0.0000i   0.0000 + 0.0000i      NaN +    NaNi

I want to extract each row of AR which comes a 1 x 10 size. what loops i will use here.

I am using this codes, but it gives wrong answer.

for ii = 1:numel(x)
     for i=1:8;
       Z(i)=abs(AR(i,ii));
     end
end

What is wrong in above codes. I want to exract each rows of AR separtely.

[KSSV]

AR(i,:)

where i is a row index.

[Arthur Roué]

What are you trying to do ? Do you want to compute the absolute value of each element in another matrix ?

[ASHA RANI]

I want to extract each row of AR which contains 10 values corresponds to x. There are 8 rows in AR.

Then I want to plot absolute value of each row versus x.

Answer 1

[madhan ravi]

AR = num2cell(AR, 2);
celldisp(AR)

[ASHA RANI]

dont understand your response, sir...plz write collectively where I have to change.

[madhan ravi]

 plot(x, AR)

[ASHA RANI]

AR = num2cell(AR, 2);
celldisp(AR)

its working sir.

but i want to give separte name to each AR{i} for i varies 1 to 8 to use further in coding. plz help

[Stephen23]

"but i want to give separte name to each AR{i} for i varies 1 to 8 to use further in coding."

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

Dynamically naming variables does not help your further coding. Using indexing is the best approach.

[ASHA RANI]

how I do indexing here, sir

[ASHA RANI]

AR=abs(cell2mat(AR));

AR1=AR(1,:);

AR2=AR(2,:);

AR3=AR(3,:);

AR4=AR(4,:);

AR5=AR(5,:);

AR6=AR(6,:);

AR7=AR(7,:);

AR8=AR(8,:);

what I do here to short my codes

[Stephen23]

"what I do here to short my codes"

Indexing is the way to shorten your code: simply access the data directly from AR.

Dynamically naming variables will make your code complex and slow.

[ASHA RANI]

I want to plot each AR1, AR2, AR3, ....,AR8 versus x, then how i do indexing, sir?

[Stephen23]

for ii = 1:size(AR,1)
    V = AR(ii,:);
    plot(V)
    ... save plot or whatever
end

Or simply plot all of the data as separate lines by tranposing the matrix:

plot(AR.')