How can I to convert a cell to a double without losing the leading zeros?
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pink flower
le 20 Sep 2020
Commenté : Star Strider
le 20 Sep 2020
I have a loop where I am trying to extract the numbers and convert them to double. However, when the numbers are "0000", the result is just "0". How can I do this?
for x = 1:length(ix20);
namex = files(i).name;
sss=regexp(namex, '(?:\d{4})\>','match');
format longg;
hm(x)=str2double(sss);
end
2 commentaires
David Hill
le 20 Sep 2020
I don't understand what you are trying to do. Please explain with an example (input and expected output). The double of '0000' is 0.
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Star Strider
le 20 Sep 2020
It is not possible to retain leading zeros in a numeric representation, such as double. To retain leading zeros, they must be kept as character arrays (single quotes) or string variables (double quotes).
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2 commentaires
Star Strider
le 20 Sep 2020
The leading zeros would disappear if your converted them to numeric values.
out = compose("%04d", 0:5:20).'
DT = datetime(out, 'InputFormat',"HHmm", 'Format','HH:mm')
producing:
out =
5×1 string array
"0000"
"0005"
"0010"
"0015"
"0020"
DT =
5×1 datetime array
00:00
00:05
00:10
00:15
00:20
The ‘DT’ vector would then be saved as a datetime array (call it anything you wish), with the leading zeros intact, and converted to hours and minutes as well. (The 'InputFormat' string specifies how the input is parsed, and the 'Format' string specifies how it is displayed.)
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