Filling in 8x8 matrix with formula

I want to create a 8x8 matrix and fill in the values using a formula. This is the workflow I have in mind is to create some nested for loop that does this:

1. I create a empty matrix A using A = zeros(8,8)
2. I create variables p(i) using (pi/16)+(i-1)*(pi/8)
3. I create a(i,j) = cos((j-1)*p(i)) to fill in matrix

This is what I have tried:

A = zeros(8,8)

for i = 1:8
    p(i) = (pi/16)+(i-1)*(pi/8)
    for i = 1:8
        for j = 1:8
            A(i,j) = cos((j-1)*p(i))

Thank you

Answer 1

[KSSV]

A = zeros(8,8)

for i = 1:8
    p = (pi/16)+(i-1)*(pi/8)
    for j = 1:8
        A(i,j) = cos((j-1)*p)
    end
 end
    

As the input values of cos are very small...all of them are 1....check your formula is it correct?

[Dani Matso]

Thanks a lot for helping KSSV! Is the (i) in p not necessary in the code? Because there are eight different p's.

The formula for p is:

pi = π/16 + (i − 1)π/8 , for i = 1, 2, . . . , 8. So I get: p1 = π/16 , p2 = 3π/16 , · · · , p8 = 15π/16

Secondly:

The matrix A(i,j) is given by cos((j-1)pi)

I think your code implements this correctly, if you have no corrections based on my new information I will mark this as the accepted answer:-)

[KSSV]

A = zeros(8,8)
for i = 1:8
    p = (pi/16)+(i-1)*(pi/8)
    for j = 1:8
        A(i,j) = cos((j-1)*p)
    end
end

See that as you wanted, the p is changing the value...it follows as you said.