Is there a way to count within the pattern, different points in a graph before repeating?

1 vue (au cours des 30 derniers jours)
For these graphs shown (both are same), is there a way to find out how many unique points there are before repeating again? For example, this graph shows there are 4 unique points and after that it just repeats the pattern. So I would like to find a way to output the 4 wihtout me manually counting (or no. of unique points depending on the pattern).

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darova
darova le 19 Fév 2021
You can round data to integer and use unique
x0 = rand(10,1);
x1 = round(10*x0); % round data to 1 symbol after the dot
unique(x1)
  2 commentaires
Prayash Thapa
Prayash Thapa le 25 Fév 2021
The x-axis values increases but I would like the code to consider the y-axis values which repeats its unqiue values depending on the order. The y-axis is the part I want to consider if that makes sense. E.G. The graph shown has 4 different unique points before it repeats, lets say the unique points are 1,3,4,6 that is shown in the y-axis. Ignoring the x-axis, I would like to know how to display this order of 1,3,4,6.
darova
darova le 25 Fév 2021
unique can return indices too
[C,ia,ic] = unique(A) %also returns index vectors ia and ic using any of the previous syntaxes.
%If A is a vector, then C = A(ia) and A = C(ic).
see more help: LINK

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