STILL confused on Solver (tried a different approach) NOT SPAM

1 vue (au cours des 30 derniers jours)
Rebecca Reyes
Rebecca Reyes le 13 Avr 2021
Commenté : Rebecca Reyes le 14 Avr 2021
please look over my new attempt
the answer for x is suppposed to be 88. I can't seem to get the answer
I am not trying to spam I just tried a new approach. Please Please help.
This is my approach.
clear dlc
%feed composition
z1=.5;
z2=.1;
z3=.15;
z4=.25;
%other given data
F=150;
PD=250;
T=10;
L=150-x;
F=150;
%k-values from chart yi/xi
k1=56;
k2=0.65;
k3=0.175;
k4=0.055;
%total balances
x1=(F*z1)/(k1*x+L);
x2=(F*z2)/(k2*x+L);
x3=(F*z3)/(k3*x+L);
x4=(F*z4)/(k4*x+L);
eqn=k1*x1+k2*x2+k3*x3+k4*x4==1;
sol=solve(eqn);
The only answer I get in command window this time is
>> Project (which is the name of the file)
  4 commentaires
Cris LaPierre
Cris LaPierre le 13 Avr 2021
You haven't declared what x is, so your code is returning an error. Did you mean to make it symbolic?
Rebecca Reyes
Rebecca Reyes le 13 Avr 2021
Yes, i think? x is what I'm hoping to solve for in the solver.

Connectez-vous pour commenter.

Réponse acceptée

Cris LaPierre
Cris LaPierre le 13 Avr 2021
Assuming x is symbolic
%feed composition
z1=.5;
z2=.1;
z3=.15;
z4=.25;
%other given data
F=150;
PD=250;
T=10;
syms x
L=150-x;
%k-values from chart yi/xi
k1=56;
k2=0.65;
k3=0.175;
k4=0.055;
%total balances
x1=(F*z1)/(k1*x+L);
x2=(F*z2)/(k2*x+L);
x3=(F*z3)/(k3*x+L);
x4=(F*z4)/(k4*x+L);
eqn=k1*x1+k2*x2+k3*x3+k4*x4==1
eqn = 
sol=solve(eqn)
sol = 
double(sol)
ans = 4×1
150.0000 88.6523 173.8927 395.3987
It looks like there are 4 possible solutions to your equation, of which, a value close to 88 is one of them. If I solve your equation substituting in a value of 88, the result is close to 1.
double(subs(lhs(eqn),x,88))
ans = 1.0052
  3 commentaires
Cris LaPierre
Cris LaPierre le 14 Avr 2021
If you use the exact values returned, every one of them will give you a result of 1. Otherwise, they wouldn't be a solution to the equation. It sounds like you need to maybe come up with a constraint for the solution, like it must be less than 100, for example.
Rebecca Reyes
Rebecca Reyes le 14 Avr 2021
Oh I see. Thank you!

Connectez-vous pour commenter.

Plus de réponses (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by