# How to shorten the amount of decimals?

2 views (last 30 days)
Garrett on 20 May 2021
Commented: Steven Lord on 20 May 2021
I keep getting really long numerical values as output:
An =
0.024234995896557227359496464702679*alpha
0.15943782393832228295849338860996*alpha
-0.12536421301907562828842055676579*alpha
-0.03553313448766475646513348990721*alpha
-0.13243736773001789371670675334921*alpha
-1.1264101534225156844164497805098*alpha
0.032972016135334102699585911872833*alpha
0.10090249826183501633095025194958*alpha
0.094800519200094255394106279895626*alpha
-0.031355837620080097288391753550103*alpha
How can i reduce this to only a couple decimal places?
Entire code for reference:
clc
clear
N = 19;
AR = 6;
n =1:2:N;
b = 6;
Vinf = 1;
c = 1;
deltay = b./(N+1);
y0n = -(b./2)+n.*deltay;
syms alpha
A = sym('A', [1, N]);
A = A(1:2:end);
Pi = sym(pi);
theta = (linspace((Pi/6),(Pi/2),numel(n)).');
S1 = sum(A.*sin(n.*(theta)));
S2 = sum(n.*A.*(sin(n.*(theta))./sin((theta))));
eq1 = (2*AR/pi)*S1+S2 == alpha;
[A,b] = equationsToMatrix(eq1, A);
x = linsolve (A,b);
An = vpa(x)

Star Strider on 20 May 2021
Use the digits function.
Steven Lord on 20 May 2021
You can instead call vpa with two inputs if you don't want to affect the number of digits for future calls.