Cody

# Problem 1158. Sum the elements in either diagonal of a square matrix

Solution 2544387

Submitted on 14 Jun 2020
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### Test Suite

Test Status Code Input and Output
1   Fail
x = ones(2); y_correct = 4; assert(isequal(sumDiagonalElements(x),y_correct))

Index exceeds the number of array elements (4). Error in sumDiagonalElements (line 2) y = sum(diag(x))+sum(diag(fliplr(x)))-(mod(numel(x),2)==0)*x(numel(x)+1)/2; Error in Test1 (line 3) assert(isequal(sumDiagonalElements(x),y_correct))

2   Fail
x = ones(3); y_correct = 5; assert(isequal(sumDiagonalElements(x),y_correct))

Index exceeds the number of array elements (9). Error in sumDiagonalElements (line 2) y = sum(diag(x))+sum(diag(fliplr(x)))-(mod(numel(x),2)==0)*x(numel(x)+1)/2; Error in Test2 (line 3) assert(isequal(sumDiagonalElements(x),y_correct))

3   Fail
x = magic(8); y_correct = 520; assert(isequal(sumDiagonalElements(x),y_correct))

Index exceeds the number of array elements (64). Error in sumDiagonalElements (line 2) y = sum(diag(x))+sum(diag(fliplr(x)))-(mod(numel(x),2)==0)*x(numel(x)+1)/2; Error in Test3 (line 3) assert(isequal(sumDiagonalElements(x),y_correct))

4   Fail
x = magic(9); y_correct = 697; assert(isequal(sumDiagonalElements(x),y_correct))

Index exceeds the number of array elements (81). Error in sumDiagonalElements (line 2) y = sum(diag(x))+sum(diag(fliplr(x)))-(mod(numel(x),2)==0)*x(numel(x)+1)/2; Error in Test4 (line 3) assert(isequal(sumDiagonalElements(x),y_correct))