Cody

# Problem 44455. Find the average of a random sequance

Solution 1536695

Submitted on 22 May 2018 by avi kiko
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### Test Suite

Test Status Code Input and Output
1   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'regexp')),'regexp hacks are forbidden')

2   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'sum')),'sum() function is forbidden')

3   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'mean')),'mean() function is forbidden')

4   Pass
rng(1); av_correct = 5.5; assert(isequal(MeanWhile(),av_correct))

a = 4 shum = 4 a = 7 shum = 11 a = 0 average = 5.5000

5   Pass
rng(2); av_correct = 4; assert(isequal(MeanWhile(),av_correct))

a = 4 shum = 4 a = 0 average = 4

6   Pass
rng(3); av_correct = 5.25; assert(isequal(MeanWhile(),av_correct))

a = 6 shum = 6 a = 7 shum = 13 a = 3 shum = 16 a = 5 shum = 21 a = 9 shum = 30 a = 9 shum = 39 a = 1 shum = 40 a = 2 shum = 42 a = 0 average = 5.2500

7   Pass
rng(7); av_correct = 0; assert(isequal(MeanWhile(),av_correct))

a = 0 average = 0

8   Pass
rng(0); av_correct = 6.571428571428571; assert(isequal(MeanWhile(),av_correct))

a = 8 shum = 8 a = 9 shum = 17 a = 1 shum = 18 a = 10 shum = 28 a = 6 shum = 34 a = 1 shum = 35 a = 3 shum = 38 a = 6 shum = 44 a = 10 shum = 54 a = 10 shum = 64 a = 1 shum = 65 a = 10 shum = 75 a = 10 shum = 85 a = 5 shum = 90 a = 8 shum = 98 a = 1 shum = 99 a = 4 shum = 103 a = 10 shum = 113 a = 8 shum = 121 a = 10 shum = 131 a = 7 shum = 138 a = 0 average = 6.5714