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Problem 44455. Find the average of a random sequance

Solution 3814453

Submitted on 24 Nov 2020 by Alisio
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Test Suite

Test Status Code Input and Output
1   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'regexp')),'regexp hacks are forbidden')
2   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'sum')),'sum() function is forbidden')
3   Pass
filetext = fileread('MeanWhile.m'); assert(isempty(strfind(filetext, 'mean')),'mean() function is forbidden')
4   Pass
rng(1); av_correct = 5.5; assert(isequal(MeanWhile(),av_correct))

ans = logical 1 ans = logical 1 average = 5.5000
5   Pass
rng(2); av_correct = 4; assert(isequal(MeanWhile(),av_correct))

ans = logical 1 average = 4
6   Pass
rng(3); av_correct = 5.25; assert(isequal(MeanWhile(),av_correct))

ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 average = 5.2500
7   Pass
rng(7); av_correct = 0; assert(isequal(MeanWhile(),av_correct))
8   Pass
rng(0); av_correct = 6.571428571428571; assert(isequal(MeanWhile(),av_correct))

ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 ans = logical 1 average = 6.5714

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