{"group":{"id":1,"name":"Community","lockable":false,"created_at":"2012-01-18T18:02:15.000Z","updated_at":"2026-04-06T14:01:22.000Z","description":"Problems submitted by members of the MATLAB Central community.","is_default":true,"created_by":161519,"badge_id":null,"featured":false,"trending":false,"solution_count_in_trending_period":0,"trending_last_calculated":"2026-04-06T00:00:00.000Z","image_id":null,"published":true,"community_created":false,"status_id":2,"is_default_group_for_player":false,"deleted_by":null,"deleted_at":null,"restored_by":null,"restored_at":null,"description_opc":null,"description_html":null,"published_at":null},"problems":[{"id":2153,"title":"Replace pattern 0 1 0 and 1 0 1","description":"Find and replace a pattern in a row of zeroes and ones.\r\n\r\n* Find 1 0 1 and replace it with 1 1 1\r\n* Find 0 1 0 and replace it with 0 0 0 \r\n\r\nExample:\r\n\r\n Input : [ 1 1 1 0 1 1 0 0 0 1 0 0 0 ]\r\n Output: [ 1 1 1 1 1 1 0 0 0 0 0 0 0 ]\r\n\r\n","description_html":"\u003cp\u003eFind and replace a pattern in a row of zeroes and ones.\u003c/p\u003e\u003cul\u003e\u003cli\u003eFind 1 0 1 and replace it with 1 1 1\u003c/li\u003e\u003cli\u003eFind 0 1 0 and replace it with 0 0 0\u003c/li\u003e\u003c/ul\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e Input : [ 1 1 1 0 1 1 0 0 0 1 0 0 0 ]\r\n Output: [ 1 1 1 1 1 1 0 0 0 0 0 0 0 ]\u003c/pre\u003e","function_template":"function y = replace_pattern(x)\r\n  y = x;\r\nend","test_suite":"%%\r\nx =         [1 0 1 1 0 0 1 0 0 1 1 1 1 0 0 0];\r\ny_correct = [1 1 1 1 0 0 0 0 0 1 1 1 1 0 0 0];\r\nassert(isequal(replace_pattern(x),y_correct))\r\n\r\n%%\r\nx =         [0 1 1 1 0 1 1 0 0 1 1 0 0 1 0 0 1 0 0 1];\r\ny_correct = [0 1 1 1 1 1 1 0 0 1 1 0 0 0 0 0 0 0 0 1];\r\nassert(isequal(replace_pattern(x),y_correct))\r\n\r\n%%\r\nx = [ones(1,10); ones(1,10); zeros(1,10)];\r\nx = x(:)';\r\ny_correct = [ones(1,29) 0];\r\nassert(isequal(replace_pattern(x),y_correct))\r\n\r\n%%\r\nx =         [1 1 1 0 1 1 1 0 1 1 0 1 1 0 1 1 0 0 1 0 0 1 0 0 0 1];\r\ny_correct = [1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 1];\r\nassert(isequal(replace_pattern(x),y_correct))\r\n\r\n%%\r\nx = [ones(1,250) zeros(1,250), ones(1,250) zeros(1,250)];\r\ny_correct = x;\r\nx([3,35,67,100,103,201]) = 0;\r\nx([257,301,333,404]) = 1;\r\nx([505,606,616]) = 0;\r\nx(997) = 1;\r\nassert(isequal(replace_pattern(x),y_correct))","published":true,"deleted":false,"likes_count":1,"comments_count":3,"created_by":22350,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":159,"test_suite_updated_at":"2017-03-15T17:02:55.000Z","rescore_all_solutions":false,"group_id":21,"created_at":"2014-02-05T18:36:21.000Z","updated_at":"2026-02-16T09:48:44.000Z","published_at":"2014-02-05T18:46:30.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFind and replace a pattern in a row of zeroes and ones.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFind 1 0 1 and replace it with 1 1 1\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFind 0 1 0 and replace it with 0 0 0\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ Input : [ 1 1 1 0 1 1 0 0 0 1 0 0 0 ]\\n Output: [ 1 1 1 1 1 1 0 0 0 0 0 0 0 ]]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2329,"title":"Finding the next number in a number list, are you able to crack it!","description":"So it goes like this, I give a number list and you find the next value!\r\n\r\nI found a way to do it, just wondering how many others can to! \r\n\r\nThis could be a fun test of skill!  Please try and see if you can get it!\r\n\r\nExample:\r\n\r\n   x =  [ ...\r\n    11;\r\n     4;\r\n    16;\r\n     3;\r\n     3;\r\n    15;\r\n     6;\r\n    17;\r\n    10;\r\n    18;\r\n     7;\r\n    13;\r\n    15;\r\n     5;\r\n    24;\r\n     5;\r\n     3;\r\n     3];\r\n NextValue = 3;\r\n\r\n %% Next value after x(1), so your finding the ? in sequence x = [?; 11; 4; 16; 3; ... 3];\r\n\r\nGood luck, just saying, it is tricky!  Many have solved this, but the key is to find the pattern...","description_html":"\u003cp\u003eSo it goes like this, I give a number list and you find the next value!\u003c/p\u003e\u003cp\u003eI found a way to do it, just wondering how many others can to!\u003c/p\u003e\u003cp\u003eThis could be a fun test of skill!  Please try and see if you can get it!\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e   x =  [ ...\r\n    11;\r\n     4;\r\n    16;\r\n     3;\r\n     3;\r\n    15;\r\n     6;\r\n    17;\r\n    10;\r\n    18;\r\n     7;\r\n    13;\r\n    15;\r\n     5;\r\n    24;\r\n     5;\r\n     3;\r\n     3];\r\n NextValue = 3;\u003c/pre\u003e\u003cpre\u003e %% Next value after x(1), so your finding the ? in sequence x = [?; 11; 4; 16; 3; ... 3];\u003c/pre\u003e\u003cp\u003eGood luck, just saying, it is tricky!  Many have solved this, but the key is to find the pattern...\u003c/p\u003e","function_template":"function NextNumber = FindNextNumber(x)\r\n  NextNumber = x;\r\nend","test_suite":"%%\r\nx =  [11;\r\n     4;\r\n    16;\r\n     3;\r\n     3;\r\n    15;\r\n     6;\r\n    17;\r\n    10;\r\n    18;\r\n     7;\r\n    13;\r\n    15;\r\n     5;\r\n    24;\r\n     5;\r\n     3;\r\n     3];\r\nNextNumber= 3;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [9;\r\n     1;\r\n     7;\r\n     1;\r\n     7;\r\n     9;\r\n     2;\r\n     8;\r\n     4;\r\n     8;\r\n    16;\r\n    21;\r\n    13;\r\n    15;\r\n     1;\r\n    13;\r\n    10];\r\nNextNumber= 8;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [6;\r\n    20;\r\n     9;\r\n     3;\r\n    25;\r\n     4;\r\n     1;\r\n     4;\r\n     8;\r\n     9;\r\n     1;\r\n     7];\r\nNextNumber= 1;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [17;\r\n     5;\r\n    12;\r\n    33;\r\n     5;\r\n     7;\r\n     4];\r\nNextNumber= 4;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [8;\r\n     6;\r\n    11;\r\n     4;\r\n     1;\r\n     6;\r\n     2;\r\n     1;\r\n     3;\r\n    11;\r\n     4;\r\n    16;\r\n     3;\r\n     3;\r\n    15;\r\n     6;\r\n    17;\r\n    10;\r\n    18;\r\n     7;\r\n    13;\r\n    15;\r\n     5;\r\n    24;\r\n     5;\r\n     3;\r\n     3;\r\n     1;\r\n     2;\r\n     5;\r\n    16;\r\n     1;\r\n     2;\r\n    17;\r\n     9;\r\n     8;\r\n     5;\r\n    12;\r\n    16;\r\n    11;\r\n     8;\r\n     5;\r\n    10;\r\n    11;\r\n    10;\r\n    10;\r\n     2;\r\n     4;\r\n    17;\r\n     5;\r\n    12;\r\n    33;\r\n     5;\r\n     7;\r\n     4;\r\n    11;\r\n    16;\r\n     5;\r\n     1;\r\n     6;\r\n    20;\r\n     9;\r\n     3;\r\n    25;\r\n     4;\r\n     1];\r\nNextNumber= 5;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [4;\r\n     4;\r\n    18;\r\n    12;\r\n    27;\r\n    20;\r\n    24;\r\n    25;\r\n    14;\r\n    29;\r\n    16;\r\n    25;\r\n    15;\r\n     6;\r\n     6;\r\n     3;\r\n    20;\r\n     9;\r\n    20;\r\n     5;\r\n    12;\r\n    24;\r\n    16;\r\n    27];\r\nNextNumber= 20;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [14;\r\n    22;\r\n    27;\r\n    15;\r\n     8;\r\n    30;\r\n    24;\r\n    33;\r\n    28;\r\n    27;\r\n    31;\r\n    31;\r\n    38;\r\n    29;\r\n    30;\r\n    35;\r\n    12;\r\n     7;\r\n    15;\r\n    22;\r\n    10;\r\n    26;\r\n    35;\r\n    15;\r\n    25;\r\n    18;\r\n    32;\r\n    30;\r\n    31;\r\n    35;\r\n    22;\r\n    15;\r\n    21;\r\n    13;\r\n    19;\r\n    24;\r\n    32;\r\n    18;\r\n    30;\r\n    31;\r\n    28;\r\n    32;\r\n    40;\r\n    17;\r\n    15;\r\n    28;\r\n    41;\r\n    42;\r\n    35;\r\n    30;\r\n    35;\r\n    39;\r\n    33;\r\n    17;\r\n    34;\r\n    26;\r\n    13;\r\n    14;\r\n    19;\r\n    40;\r\n    13;\r\n    27;\r\n    16;\r\n    23;\r\n    22;\r\n    29;\r\n    42;\r\n    33;\r\n    37;\r\n    28;\r\n    36;\r\n    30;\r\n    26;\r\n     6;\r\n    25;\r\n    39;\r\n    26;\r\n    23;\r\n    39;\r\n    27;\r\n    28;\r\n    14;\r\n    25;\r\n    29;\r\n     7;\r\n    16];\r\nNextNumber= 35;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%    \r\nx = [27;\r\n    31;\r\n    31;\r\n    38;\r\n    29;\r\n    30;\r\n    35;\r\n    12;\r\n     7;\r\n    15;\r\n    22;\r\n    10;\r\n    26;\r\n    35;\r\n    15;\r\n    25;\r\n    18;\r\n    32;\r\n    30;\r\n    31;\r\n    35;\r\n    22;\r\n    15;\r\n    21;\r\n    13;\r\n    19;\r\n    24;\r\n    32;\r\n    18;\r\n    30;\r\n    31;\r\n    28;\r\n    32;\r\n    40;\r\n    17;\r\n    15;\r\n    28;\r\n    41;\r\n    42;\r\n    35;\r\n    30;\r\n    35;\r\n    39;\r\n    33;\r\n    17;\r\n    34;\r\n    26;\r\n    13;\r\n    14;\r\n    19;\r\n    40;\r\n    13;\r\n    27;\r\n    16;\r\n    23;\r\n    22;\r\n    29;\r\n    42;\r\n    33;\r\n    37;\r\n    28;\r\n    36;\r\n    30;\r\n    26;\r\n     6;\r\n    25;\r\n    39;\r\n    26;\r\n    23;\r\n    39;\r\n    27;\r\n    28;\r\n    14;\r\n    25;\r\n    29;\r\n     7;\r\n    16;\r\n    28;\r\n    11;\r\n    14];\r\nNextNumber= 28;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [39;\r\n    46;\r\n    39;\r\n    21;\r\n    46;\r\n    46;\r\n    45;\r\n    31;\r\n    47;\r\n    45;\r\n    39;\r\n    44;\r\n    47];\r\nNextNumber= 45;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [7;\r\n     8;\r\n    18;\r\n     7;\r\n     9;\r\n     2;\r\n    11;\r\n     2;\r\n     2;\r\n     2;\r\n    13;\r\n     4;\r\n     4;\r\n    13;\r\n    11;\r\n     6;\r\n     3;\r\n    15;\r\n    16;\r\n    17;\r\n     4;\r\n     7;\r\n    17;\r\n    12;\r\n     3;\r\n    12;\r\n     9;\r\n     3;\r\n    17;\r\n     2;\r\n     4;\r\n    17;\r\n     5;\r\n    18;\r\n     1;\r\n     4;\r\n    15;\r\n     2;\r\n    11;\r\n     6;\r\n    19;\r\n     4;\r\n     2;\r\n     1;\r\n    18;\r\n    15;\r\n    12;\r\n    17;\r\n    11;\r\n     2;\r\n     1;\r\n     3;\r\n    17;\r\n    15;\r\n     4;\r\n    12;\r\n    10;\r\n    11;\r\n    16;\r\n     4;\r\n     2;\r\n    13;\r\n    13;\r\n     8;\r\n    16;\r\n     2;\r\n     9;\r\n    19;\r\n     7;\r\n    15;\r\n    12;\r\n     5;\r\n    17;\r\n     6;\r\n     9;\r\n    16;\r\n     9;\r\n    11;\r\n     4;\r\n    12;\r\n     7;\r\n    12;\r\n     9;\r\n    18;\r\n     2;\r\n     8;\r\n    14];\r\nNextNumber= 4;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":2,"created_by":15013,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":16,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-05-16T23:24:44.000Z","updated_at":"2014-05-19T14:19:51.000Z","published_at":"2014-05-16T23:24:59.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eSo it goes like this, I give a number list and you find the next value!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eI found a way to do it, just wondering how many others can to!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThis could be a fun test of skill! Please try and see if you can get it!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[   x =  [ ...\\n    11;\\n     4;\\n    16;\\n     3;\\n     3;\\n    15;\\n     6;\\n    17;\\n    10;\\n    18;\\n     7;\\n    13;\\n    15;\\n     5;\\n    24;\\n     5;\\n     3;\\n     3];\\n NextValue = 3;\\n\\n %%Next value after x(1), so your finding the ? in sequence x = [?; 11; 4; 16; 3; ... 3];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eGood luck, just saying, it is tricky! Many have solved this, but the key is to find the pattern...\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2562,"title":"Juggling","description":"There is a notation system for \u003chttp://en.wikipedia.org/wiki/Juggling jugglers\u003e called \u003chttp://en.wikipedia.org/wiki/Siteswap siteswap\u003e\r\n\r\nLet consider the simplest version called vanilla siteswap.\r\n\r\nA siteswap pattern consist of a list of nonnegative integers being instructions for a juggler.\r\n\r\nWhile juggling, he throws up maximum one ball at the time at given by the pattern height (and then catches it after given periods). 0 means \"missing\", 1 is passing ball between hands,  2 is keeping ball for a moment (no toss), 3 is cascade toss, etc. (see \u003chttp://en.wikipedia.org/wiki/Siteswap Wikipedia\u003e)\r\n\r\nAfter one full cycle pattern is looped and can be performed continuously. This allows simple patterns to be very short, i.e. classical pattern for three balls noted as 333333... is written by only one 3.\r\n\r\nFor example pattern *51* uses three balls like that:     \r\n\r\n\u003c\u003chttp://upload.wikimedia.org/wikipedia/commons/thumb/3/35/Douche3b.gif/120px-Douche3b.gif\u003e\u003e\r\n\r\nand pattern *3* looks like this:\r\n\r\n\u003c\u003chttp://upload.wikimedia.org/wikipedia/commons/thumb/2/26/3-ball_cascade_movie.gif/220px-3-ball_cascade_movie.gif\u003e\u003e\r\n\r\nIn this problem we will consider such defined patterns. Catching and throwing up to one ball at a time is allowed. Given a vector of integers, determine if it is a valid pattern and return number of balls required (it's an average of pattern) or NaN instead.\r\n\r\n Input: [3]   Output:[3]\r\n\r\n Input: [441] Output:[3]\r\n\r\n Input: [521] Output:[NaN] (average is not an integer)\r\n\r\n Input: [321] Output:[NaN] (proper average, but balls meet together)\r\n\r\n(All illustrations courtesy of Wikipedia)","description_html":"\u003cp\u003eThere is a notation system for \u003ca href = \"http://en.wikipedia.org/wiki/Juggling\"\u003ejugglers\u003c/a\u003e called \u003ca href = \"http://en.wikipedia.org/wiki/Siteswap\"\u003esiteswap\u003c/a\u003e\u003c/p\u003e\u003cp\u003eLet consider the simplest version called vanilla siteswap.\u003c/p\u003e\u003cp\u003eA siteswap pattern consist of a list of nonnegative integers being instructions for a juggler.\u003c/p\u003e\u003cp\u003eWhile juggling, he throws up maximum one ball at the time at given by the pattern height (and then catches it after given periods). 0 means \"missing\", 1 is passing ball between hands,  2 is keeping ball for a moment (no toss), 3 is cascade toss, etc. (see \u003ca href = \"http://en.wikipedia.org/wiki/Siteswap\"\u003eWikipedia\u003c/a\u003e)\u003c/p\u003e\u003cp\u003eAfter one full cycle pattern is looped and can be performed continuously. This allows simple patterns to be very short, i.e. classical pattern for three balls noted as 333333... is written by only one 3.\u003c/p\u003e\u003cp\u003eFor example pattern \u003cb\u003e51\u003c/b\u003e uses three balls like that:\u003c/p\u003e\u003cimg src = \"http://upload.wikimedia.org/wikipedia/commons/thumb/3/35/Douche3b.gif/120px-Douche3b.gif\"\u003e\u003cp\u003eand pattern \u003cb\u003e3\u003c/b\u003e looks like this:\u003c/p\u003e\u003cimg src = \"http://upload.wikimedia.org/wikipedia/commons/thumb/2/26/3-ball_cascade_movie.gif/220px-3-ball_cascade_movie.gif\"\u003e\u003cp\u003eIn this problem we will consider such defined patterns. Catching and throwing up to one ball at a time is allowed. Given a vector of integers, determine if it is a valid pattern and return number of balls required (it's an average of pattern) or NaN instead.\u003c/p\u003e\u003cpre\u003e Input: [3]   Output:[3]\u003c/pre\u003e\u003cpre\u003e Input: [441] Output:[3]\u003c/pre\u003e\u003cpre\u003e Input: [521] Output:[NaN] (average is not an integer)\u003c/pre\u003e\u003cpre\u003e Input: [321] Output:[NaN] (proper average, but balls meet together)\u003c/pre\u003e\u003cp\u003e(All illustrations courtesy of Wikipedia)\u003c/p\u003e","function_template":"function n = siteswap(pattern)\r\n  n=mean(pattern);\r\nend","test_suite":"%%\r\npattern = 1;\r\ny_correct = 1;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = 2;\r\ny_correct = 2;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = 3;\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [3 3];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 5 1];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 5 2];\r\ny_correct = 4;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [3 2 1];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [3 1 2];\r\ny_correct = 2;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [4 4 1];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 2 1];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 5 5 0 0];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 3 1];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [6 4 5 1];\r\ny_correct = 4;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [7 3 3 3];\r\ny_correct = 4;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [7 1];\r\ny_correct = 4;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 3 1 4 5 3 0 5 5 2 0];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [3 4 2];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [7 7 1];\r\ny_correct = 5;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [1 4 0 3];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [1 3 0 4];\r\ny_correct = 2;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n\r\n%%\r\na=randi(100)\r\npattern = [4*a, 0, 4*a-1, 1];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\na=randi(100)\r\npattern = [4*a, 0, 1, 4*a-1];\r\ny_correct = 2*a;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\nassert(isequaln(siteswap([6 0 1 5]),siteswap([6 0 5 1])))","published":true,"deleted":false,"likes_count":7,"comments_count":0,"created_by":14358,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":25,"test_suite_updated_at":"2014-09-12T09:06:19.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2014-09-08T12:38:05.000Z","updated_at":"2026-01-31T12:47:55.000Z","published_at":"2014-09-08T12:38:05.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/media/image1.gif\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/media/image2.gif\"}],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThere is a notation system for\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://en.wikipedia.org/wiki/Juggling\\\"\u003e\u003cw:r\u003e\u003cw:t\u003ejugglers\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e called\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://en.wikipedia.org/wiki/Siteswap\\\"\u003e\u003cw:r\u003e\u003cw:t\u003esiteswap\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eLet consider the simplest version called vanilla siteswap.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eA siteswap pattern consist of a list of nonnegative integers being instructions for a juggler.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eWhile juggling, he throws up maximum one ball at the time at given by the pattern height (and then catches it after given periods). 0 means \\\"missing\\\", 1 is passing ball between hands, 2 is keeping ball for a moment (no toss), 3 is cascade toss, etc. (see\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://en.wikipedia.org/wiki/Siteswap\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eWikipedia\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eAfter one full cycle pattern is looped and can be performed continuously. This allows simple patterns to be very short, i.e. classical pattern for three balls noted as 333333... is written by only one 3.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example pattern\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e51\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e uses three balls like that:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eand pattern\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e3\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e looks like this:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId2\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eIn this problem we will consider such defined patterns. Catching and throwing up to one ball at a time is allowed. Given a vector of integers, determine if it is a valid pattern and return number of balls required (it's an average of pattern) or NaN instead.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ Input: [3]   Output:[3]\\n\\n Input: [441] Output:[3]\\n\\n Input: [521] Output:[NaN] (average is not an integer)\\n\\n Input: [321] Output:[NaN] (proper average, but balls meet together)]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e(All illustrations courtesy of Wikipedia)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" 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Zero Zero Zero!!!","description":"Hello all,\r\nSo you have to find the largest section of zeros in a vector and then find the length of those zeros and there starting position...\r\nFor example:\r\n  \r\n  x = [1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 0 9 8 7 6 5 4 3 2 1];\r\n  %then the output is:\r\n  LP = [9 10] %[Length Position]\r\n  \r\n  %Or another example:\r\n  \r\n  x = [1 0 3 49 3 2 232 3 0 0 0 0 0 0 8 290 0 0 0 12 323 34];\r\n  %then the output is:\r\n  LP = [6 9]\r\n  \r\n  %Or another example:\r\n  \r\n  x = [1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 0];\r\n  %then the output is:\r\n  LP = [7 3];\r\n\r\nHave Fun!\r\n","description_html":"\u003cp\u003eHello all,\r\nSo you have to find the largest section of zeros in a vector and then find the length of those zeros and there starting position...\r\nFor example:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003ex = [1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 0 9 8 7 6 5 4 3 2 1];\r\n%then the output is:\r\nLP = [9 10] %[Length Position]\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e%Or another example:\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003ex = [1 0 3 49 3 2 232 3 0 0 0 0 0 0 8 290 0 0 0 12 323 34];\r\n%then the output is:\r\nLP = [6 9]\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e%Or another example:\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003ex = [1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 0];\r\n%then the output is:\r\nLP = [7 3];\r\n\u003c/pre\u003e\u003cp\u003eHave Fun!\u003c/p\u003e","function_template":"function y = LengthAndPosnZeros(x)\r\n  y = x;\r\nend","test_suite":"%%\r\nx = [1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 0 9 8 7 6 5 4 3 2 1];\r\nLP = [9 10] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 0 3 49 3 2 232 3 0 0 0 0 0 0 8 290 0 0 0 12 323 34];\r\nLP = [6 9]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 0];\r\nLP = [7 3];\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 2 0 0];\r\nLP = [2 3] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 2 0 0 0 0 0 0 0 0 0 9 0 0 0 0 0 0];\r\nLP = [9 3] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 0 0 0 0 0 0 0 0 0 1];\r\nLP = [9 2] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [111 541 0 45 3 0 0 0 15 26 0 4 84 3 84 0 9];\r\nLP = [3 6] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 0 1];\r\nLP = [1 2] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n\r\n","published":true,"deleted":false,"likes_count":15,"comments_count":1,"created_by":15013,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":540,"test_suite_updated_at":"2013-08-08T19:35:25.000Z","rescore_all_solutions":false,"group_id":13,"created_at":"2013-08-08T18:54:26.000Z","updated_at":"2026-03-24T00:57:27.000Z","published_at":"2013-08-08T19:35:25.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHello all, So you have to find the largest section of zeros in a vector and then find the length of those zeros and there starting position... For example:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[x = [1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 0 9 8 7 6 5 4 3 2 1];\\n%then the output is:\\nLP = [9 10] %[Length Position]\\n\\n%Or another example:\\n\\nx = [1 0 3 49 3 2 232 3 0 0 0 0 0 0 8 290 0 0 0 12 323 34];\\n%then the output is:\\nLP = [6 9]\\n\\n%Or another example:\\n\\nx = [1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 0];\\n%then the output is:\\nLP = [7 3];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHave Fun!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":939,"title":"DNA Pattern Match:  Performance  Metric - Speed","description":"The Challenge is to Rapidly find matches of DNA sequences, Length=6, in a 1,800,000 long DNA file.\r\n\r\nAt \u003chttp://imacst.com/issues/volume-3issue-1/ IMACST\u003e the paper \u003chttp://imacst.com/web_documents/1202002.pdf An Intelligent and Efficient Matching Algorithm to Finding a DNA Pattern\u003e claimed an astounding time improvement from  9.94 seconds to 7.84 seconds, 21% time reduction, to match six segments of length 6 in a 1.8M long DNA file. Basic probability asserts 1.8M/4^6 * 6 = 2637 matches. The paper's test case produced 2346 matches. The method employed used text processing in C++. The paper's L=25 and L=50 cases will be later challenges.\r\n\r\nMatlab can achieve matching a six pattern set of L=6 in \u003c15 msec (i5/16GB). This is merely a 99.8% time reduction.\r\n\r\n\r\n*Challenge Description:*\r\nDNA is made of letters ACGT, \u003chttp://en.wikipedia.org/wiki/DNA wiki DNA\u003e, which for the purposes of this Matlab Cody Challenge are given values 0 thru 3. (ACGT= 0123)\r\n\r\n*Input:* [DNA, DNA_ID, Patterns]\r\n\r\n* DNA is a 1.8M long uint8 row vector of values 0 thru 3.\r\n* DNA_ID identifies the DNA segment being processed. Multiple calls using the same DNA_ID will be performed. The first call of a DNA_ID is not timed.\r\n* Patterns is an Nx6 uint8 array where each row corresponds to a search pattern.\r\n\r\n*Output:* Locations\r\n\r\nLocations of all start indices that match any of the patterns\r\n\r\n*Scoring:* Average Time (msec) for a block of L=6 patterns\r\n\r\nExample:\r\n\r\n* DNA= [0 1 2 3 3 2 1 0 1 2 3 3]\r\n* Pattern = [2 3 3 2 1 0]\r\n* Locations = [3]\r\n\r\n*Hints:*\r\n\r\n* Vectorization (Base 4 to Base 10 of 6 character words)\r\n* Bitshift/Reshape to create all words\r\n* Logical Indexing\r\n \r\n\r\nComing soon: Genome DNA sequencing of PhagePhix174 and Haempphilus Influenza","description_html":"\u003cp\u003eThe Challenge is to Rapidly find matches of DNA sequences, Length=6, in a 1,800,000 long DNA file.\u003c/p\u003e\u003cp\u003eAt \u003ca href=\"http://imacst.com/issues/volume-3issue-1/\"\u003eIMACST\u003c/a\u003e the paper \u003ca href=\"http://imacst.com/web_documents/1202002.pdf\"\u003eAn Intelligent and Efficient Matching Algorithm to Finding a DNA Pattern\u003c/a\u003e claimed an astounding time improvement from  9.94 seconds to 7.84 seconds, 21% time reduction, to match six segments of length 6 in a 1.8M long DNA file. Basic probability asserts 1.8M/4^6 * 6 = 2637 matches. The paper's test case produced 2346 matches. The method employed used text processing in C++. The paper's L=25 and L=50 cases will be later challenges.\u003c/p\u003e\u003cp\u003eMatlab can achieve matching a six pattern set of L=6 in \u0026lt;15 msec (i5/16GB). This is merely a 99.8% time reduction.\u003c/p\u003e\u003cp\u003e\u003cb\u003eChallenge Description:\u003c/b\u003e\r\nDNA is made of letters ACGT, \u003ca href=\"http://en.wikipedia.org/wiki/DNA\"\u003ewiki DNA\u003c/a\u003e, which for the purposes of this Matlab Cody Challenge are given values 0 thru 3. (ACGT= 0123)\u003c/p\u003e\u003cp\u003e\u003cb\u003eInput:\u003c/b\u003e [DNA, DNA_ID, Patterns]\u003c/p\u003e\u003cul\u003e\u003cli\u003eDNA is a 1.8M long uint8 row vector of values 0 thru 3.\u003c/li\u003e\u003cli\u003eDNA_ID identifies the DNA segment being processed. Multiple calls using the same DNA_ID will be performed. The first call of a DNA_ID is not timed.\u003c/li\u003e\u003cli\u003ePatterns is an Nx6 uint8 array where each row corresponds to a search pattern.\u003c/li\u003e\u003c/ul\u003e\u003cp\u003e\u003cb\u003eOutput:\u003c/b\u003e Locations\u003c/p\u003e\u003cp\u003eLocations of all start indices that match any of the patterns\u003c/p\u003e\u003cp\u003e\u003cb\u003eScoring:\u003c/b\u003e Average Time (msec) for a block of L=6 patterns\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cul\u003e\u003cli\u003eDNA= [0 1 2 3 3 2 1 0 1 2 3 3]\u003c/li\u003e\u003cli\u003ePattern = [2 3 3 2 1 0]\u003c/li\u003e\u003cli\u003eLocations = [3]\u003c/li\u003e\u003c/ul\u003e\u003cp\u003e\u003cb\u003eHints:\u003c/b\u003e\u003c/p\u003e\u003cul\u003e\u003cli\u003eVectorization (Base 4 to Base 10 of 6 character words)\u003c/li\u003e\u003cli\u003eBitshift/Reshape to create all words\u003c/li\u003e\u003cli\u003eLogical Indexing\u003c/li\u003e\u003c/ul\u003e\u003cp\u003eComing soon: Genome DNA sequencing of PhagePhix174 and Haempphilus Influenza\u003c/p\u003e","function_template":"function Locations = find_DNA(DNA, DNA_ID, Patterns)\r\n persistent DNA_ID_loaded  % add other DNA created variables\r\n Locations=[];\r\n if isempty(DNA_ID_loaded) || DNA_ID~=DNA_ID_loaded\r\n  % Perform initialization actions on DNA vector - optional\r\n  DNA_ID_loaded=DNA_ID;\r\n  \r\n end % DNA_ID Processing\r\n\r\n\r\n\r\n \r\nend\r\n\r\n\r\n\r\n\r\n","test_suite":"%%\r\nfeval(@assignin,'caller','score',0);\r\n%%\r\n% Functionality Section\r\nPass=1;\r\nw=6;\r\nDNA=randi(4,1,1800000,'uint8')-1;\r\nPatterns=randi(4,12,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:6,:); % Take first 6 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nDNA_ID=1;\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\nif isempty(Locations),Pass=0;end\r\nif max(size(Locations))\u003c1024,Pass=0;end\r\nfor i=1:size(Locations,1)\r\n      Pass=Pass \u0026\u0026 ismember(DNA(Locations(i,end):Locations(i,end)+w-1),Patterns,'rows');\r\n    end\r\n\r\nDNA=randi(4,1,1800000,'uint8')-1;\r\nPatterns=randi(4,24,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:12,:); % Take first 6 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nDNA_ID=2;\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\nif isempty(Locations),Pass=0;end\r\nif max(size(Locations))\u003c1024,Pass=0;end\r\nfor i=1:size(Locations,1)\r\n      Pass=Pass \u0026\u0026 ismember(DNA(Locations(i,end):Locations(i,end)+w-1),Patterns,'rows');\r\n    end\r\n\r\n\r\nassert(isequal(Pass,1))\r\n%%\r\n% Timing Section\r\nDNA=randi(4,1,1800000,'uint8')-1;\r\nPatterns=randi(4,12,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:6,:); % Take first 6 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nDNA_ID=1;\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\n\r\nt0=clock;\r\nfor i=1:10\r\n Locations = find_DNA(DNA, DNA_ID, Patterns);\r\nend\r\ndt1=etime(clock,t0)*1000; % msec conversion\r\nfprintf('Your Set 1 Time = %i msec\\n',floor(dt1))\r\n\r\n\r\nPatterns=randi(4,24,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:12,:); % Take first 12 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nt0=clock;\r\nfor i=1:10\r\n Locations = find_DNA(DNA, DNA_ID, Patterns);\r\nend\r\ndt2=etime(clock,t0)*1000; % msec conversion\r\nfprintf('Your Set 2 Time = %i msec\\n',floor(dt2))\r\n\r\n\r\n% New DNA Set\r\nDNA=randi(4,1,1800000,'uint8')-1;\r\nPatterns=randi(4,12,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:6,:); % Take first 6 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nDNA_ID=2;\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\n\r\nt0=clock;\r\nfor i=1:10\r\n Locations = find_DNA(DNA, DNA_ID, Patterns);\r\nend\r\ndt3=etime(clock,t0)*1000; % msec conversion\r\nfprintf('Your Set 3 Time = %i msec\\n',floor(dt3))\r\n\r\n\r\nfeval(@assignin,'caller','score',min(400,floor(double(dt1+dt2+dt3)/30)));\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":3097,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":9,"test_suite_updated_at":"2012-09-10T03:41:37.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2012-09-10T00:09:00.000Z","updated_at":"2025-11-21T09:02:33.000Z","published_at":"2012-09-10T03:40:23.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe Challenge is to Rapidly find matches of DNA sequences, Length=6, in a 1,800,000 long DNA file.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eAt\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://imacst.com/issues/volume-3issue-1/\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eIMACST\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e the paper\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://imacst.com/web_documents/1202002.pdf\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eAn Intelligent and Efficient Matching Algorithm to Finding a DNA Pattern\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e claimed an astounding time improvement from 9.94 seconds to 7.84 seconds, 21% time reduction, to match six segments of length 6 in a 1.8M long DNA file. Basic probability asserts 1.8M/4^6 * 6 = 2637 matches. The paper's test case produced 2346 matches. The method employed used text processing in C++. The paper's L=25 and L=50 cases will be later challenges.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eMatlab can achieve matching a six pattern set of L=6 in \u0026lt;15 msec (i5/16GB). This is merely a 99.8% time reduction.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eChallenge Description:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e DNA is made of letters ACGT,\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://en.wikipedia.org/wiki/DNA\\\"\u003e\u003cw:r\u003e\u003cw:t\u003ewiki DNA\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e, which for the purposes of this Matlab Cody Challenge are given values 0 thru 3. (ACGT= 0123)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eInput:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e [DNA, DNA_ID, Patterns]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDNA is a 1.8M long uint8 row vector of values 0 thru 3.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDNA_ID identifies the DNA segment being processed. Multiple calls using the same DNA_ID will be performed. The first call of a DNA_ID is not timed.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePatterns is an Nx6 uint8 array where each row corresponds to a search pattern.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eOutput:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e Locations\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eLocations of all start indices that match any of the patterns\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eScoring:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e Average Time (msec) for a block of L=6 patterns\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDNA= [0 1 2 3 3 2 1 0 1 2 3 3]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePattern = [2 3 3 2 1 0]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eLocations = [3]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eHints:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eVectorization (Base 4 to Base 10 of 6 character words)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eBitshift/Reshape to create all words\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eLogical Indexing\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eComing soon: Genome DNA sequencing of PhagePhix174 and Haempphilus Influenza\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"errors":[],"problems":[{"id":2153,"title":"Replace pattern 0 1 0 and 1 0 1","description":"Find and replace a pattern in a row of zeroes and ones.\r\n\r\n* Find 1 0 1 and replace it with 1 1 1\r\n* Find 0 1 0 and replace it with 0 0 0 \r\n\r\nExample:\r\n\r\n Input : [ 1 1 1 0 1 1 0 0 0 1 0 0 0 ]\r\n Output: [ 1 1 1 1 1 1 0 0 0 0 0 0 0 ]\r\n\r\n","description_html":"\u003cp\u003eFind and replace a pattern in a row of zeroes and ones.\u003c/p\u003e\u003cul\u003e\u003cli\u003eFind 1 0 1 and replace it with 1 1 1\u003c/li\u003e\u003cli\u003eFind 0 1 0 and replace it with 0 0 0\u003c/li\u003e\u003c/ul\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e Input : [ 1 1 1 0 1 1 0 0 0 1 0 0 0 ]\r\n Output: [ 1 1 1 1 1 1 0 0 0 0 0 0 0 ]\u003c/pre\u003e","function_template":"function y = replace_pattern(x)\r\n  y = x;\r\nend","test_suite":"%%\r\nx =         [1 0 1 1 0 0 1 0 0 1 1 1 1 0 0 0];\r\ny_correct = [1 1 1 1 0 0 0 0 0 1 1 1 1 0 0 0];\r\nassert(isequal(replace_pattern(x),y_correct))\r\n\r\n%%\r\nx =         [0 1 1 1 0 1 1 0 0 1 1 0 0 1 0 0 1 0 0 1];\r\ny_correct = [0 1 1 1 1 1 1 0 0 1 1 0 0 0 0 0 0 0 0 1];\r\nassert(isequal(replace_pattern(x),y_correct))\r\n\r\n%%\r\nx = [ones(1,10); ones(1,10); zeros(1,10)];\r\nx = x(:)';\r\ny_correct = [ones(1,29) 0];\r\nassert(isequal(replace_pattern(x),y_correct))\r\n\r\n%%\r\nx =         [1 1 1 0 1 1 1 0 1 1 0 1 1 0 1 1 0 0 1 0 0 1 0 0 0 1];\r\ny_correct = [1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 1];\r\nassert(isequal(replace_pattern(x),y_correct))\r\n\r\n%%\r\nx = [ones(1,250) zeros(1,250), ones(1,250) zeros(1,250)];\r\ny_correct = x;\r\nx([3,35,67,100,103,201]) = 0;\r\nx([257,301,333,404]) = 1;\r\nx([505,606,616]) = 0;\r\nx(997) = 1;\r\nassert(isequal(replace_pattern(x),y_correct))","published":true,"deleted":false,"likes_count":1,"comments_count":3,"created_by":22350,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":159,"test_suite_updated_at":"2017-03-15T17:02:55.000Z","rescore_all_solutions":false,"group_id":21,"created_at":"2014-02-05T18:36:21.000Z","updated_at":"2026-02-16T09:48:44.000Z","published_at":"2014-02-05T18:46:30.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFind and replace a pattern in a row of zeroes and ones.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFind 1 0 1 and replace it with 1 1 1\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFind 0 1 0 and replace it with 0 0 0\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ Input : [ 1 1 1 0 1 1 0 0 0 1 0 0 0 ]\\n Output: [ 1 1 1 1 1 1 0 0 0 0 0 0 0 ]]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2329,"title":"Finding the next number in a number list, are you able to crack it!","description":"So it goes like this, I give a number list and you find the next value!\r\n\r\nI found a way to do it, just wondering how many others can to! \r\n\r\nThis could be a fun test of skill!  Please try and see if you can get it!\r\n\r\nExample:\r\n\r\n   x =  [ ...\r\n    11;\r\n     4;\r\n    16;\r\n     3;\r\n     3;\r\n    15;\r\n     6;\r\n    17;\r\n    10;\r\n    18;\r\n     7;\r\n    13;\r\n    15;\r\n     5;\r\n    24;\r\n     5;\r\n     3;\r\n     3];\r\n NextValue = 3;\r\n\r\n %% Next value after x(1), so your finding the ? in sequence x = [?; 11; 4; 16; 3; ... 3];\r\n\r\nGood luck, just saying, it is tricky!  Many have solved this, but the key is to find the pattern...","description_html":"\u003cp\u003eSo it goes like this, I give a number list and you find the next value!\u003c/p\u003e\u003cp\u003eI found a way to do it, just wondering how many others can to!\u003c/p\u003e\u003cp\u003eThis could be a fun test of skill!  Please try and see if you can get it!\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cpre\u003e   x =  [ ...\r\n    11;\r\n     4;\r\n    16;\r\n     3;\r\n     3;\r\n    15;\r\n     6;\r\n    17;\r\n    10;\r\n    18;\r\n     7;\r\n    13;\r\n    15;\r\n     5;\r\n    24;\r\n     5;\r\n     3;\r\n     3];\r\n NextValue = 3;\u003c/pre\u003e\u003cpre\u003e %% Next value after x(1), so your finding the ? in sequence x = [?; 11; 4; 16; 3; ... 3];\u003c/pre\u003e\u003cp\u003eGood luck, just saying, it is tricky!  Many have solved this, but the key is to find the pattern...\u003c/p\u003e","function_template":"function NextNumber = FindNextNumber(x)\r\n  NextNumber = x;\r\nend","test_suite":"%%\r\nx =  [11;\r\n     4;\r\n    16;\r\n     3;\r\n     3;\r\n    15;\r\n     6;\r\n    17;\r\n    10;\r\n    18;\r\n     7;\r\n    13;\r\n    15;\r\n     5;\r\n    24;\r\n     5;\r\n     3;\r\n     3];\r\nNextNumber= 3;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [9;\r\n     1;\r\n     7;\r\n     1;\r\n     7;\r\n     9;\r\n     2;\r\n     8;\r\n     4;\r\n     8;\r\n    16;\r\n    21;\r\n    13;\r\n    15;\r\n     1;\r\n    13;\r\n    10];\r\nNextNumber= 8;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [6;\r\n    20;\r\n     9;\r\n     3;\r\n    25;\r\n     4;\r\n     1;\r\n     4;\r\n     8;\r\n     9;\r\n     1;\r\n     7];\r\nNextNumber= 1;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [17;\r\n     5;\r\n    12;\r\n    33;\r\n     5;\r\n     7;\r\n     4];\r\nNextNumber= 4;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [8;\r\n     6;\r\n    11;\r\n     4;\r\n     1;\r\n     6;\r\n     2;\r\n     1;\r\n     3;\r\n    11;\r\n     4;\r\n    16;\r\n     3;\r\n     3;\r\n    15;\r\n     6;\r\n    17;\r\n    10;\r\n    18;\r\n     7;\r\n    13;\r\n    15;\r\n     5;\r\n    24;\r\n     5;\r\n     3;\r\n     3;\r\n     1;\r\n     2;\r\n     5;\r\n    16;\r\n     1;\r\n     2;\r\n    17;\r\n     9;\r\n     8;\r\n     5;\r\n    12;\r\n    16;\r\n    11;\r\n     8;\r\n     5;\r\n    10;\r\n    11;\r\n    10;\r\n    10;\r\n     2;\r\n     4;\r\n    17;\r\n     5;\r\n    12;\r\n    33;\r\n     5;\r\n     7;\r\n     4;\r\n    11;\r\n    16;\r\n     5;\r\n     1;\r\n     6;\r\n    20;\r\n     9;\r\n     3;\r\n    25;\r\n     4;\r\n     1];\r\nNextNumber= 5;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [4;\r\n     4;\r\n    18;\r\n    12;\r\n    27;\r\n    20;\r\n    24;\r\n    25;\r\n    14;\r\n    29;\r\n    16;\r\n    25;\r\n    15;\r\n     6;\r\n     6;\r\n     3;\r\n    20;\r\n     9;\r\n    20;\r\n     5;\r\n    12;\r\n    24;\r\n    16;\r\n    27];\r\nNextNumber= 20;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [14;\r\n    22;\r\n    27;\r\n    15;\r\n     8;\r\n    30;\r\n    24;\r\n    33;\r\n    28;\r\n    27;\r\n    31;\r\n    31;\r\n    38;\r\n    29;\r\n    30;\r\n    35;\r\n    12;\r\n     7;\r\n    15;\r\n    22;\r\n    10;\r\n    26;\r\n    35;\r\n    15;\r\n    25;\r\n    18;\r\n    32;\r\n    30;\r\n    31;\r\n    35;\r\n    22;\r\n    15;\r\n    21;\r\n    13;\r\n    19;\r\n    24;\r\n    32;\r\n    18;\r\n    30;\r\n    31;\r\n    28;\r\n    32;\r\n    40;\r\n    17;\r\n    15;\r\n    28;\r\n    41;\r\n    42;\r\n    35;\r\n    30;\r\n    35;\r\n    39;\r\n    33;\r\n    17;\r\n    34;\r\n    26;\r\n    13;\r\n    14;\r\n    19;\r\n    40;\r\n    13;\r\n    27;\r\n    16;\r\n    23;\r\n    22;\r\n    29;\r\n    42;\r\n    33;\r\n    37;\r\n    28;\r\n    36;\r\n    30;\r\n    26;\r\n     6;\r\n    25;\r\n    39;\r\n    26;\r\n    23;\r\n    39;\r\n    27;\r\n    28;\r\n    14;\r\n    25;\r\n    29;\r\n     7;\r\n    16];\r\nNextNumber= 35;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%    \r\nx = [27;\r\n    31;\r\n    31;\r\n    38;\r\n    29;\r\n    30;\r\n    35;\r\n    12;\r\n     7;\r\n    15;\r\n    22;\r\n    10;\r\n    26;\r\n    35;\r\n    15;\r\n    25;\r\n    18;\r\n    32;\r\n    30;\r\n    31;\r\n    35;\r\n    22;\r\n    15;\r\n    21;\r\n    13;\r\n    19;\r\n    24;\r\n    32;\r\n    18;\r\n    30;\r\n    31;\r\n    28;\r\n    32;\r\n    40;\r\n    17;\r\n    15;\r\n    28;\r\n    41;\r\n    42;\r\n    35;\r\n    30;\r\n    35;\r\n    39;\r\n    33;\r\n    17;\r\n    34;\r\n    26;\r\n    13;\r\n    14;\r\n    19;\r\n    40;\r\n    13;\r\n    27;\r\n    16;\r\n    23;\r\n    22;\r\n    29;\r\n    42;\r\n    33;\r\n    37;\r\n    28;\r\n    36;\r\n    30;\r\n    26;\r\n     6;\r\n    25;\r\n    39;\r\n    26;\r\n    23;\r\n    39;\r\n    27;\r\n    28;\r\n    14;\r\n    25;\r\n    29;\r\n     7;\r\n    16;\r\n    28;\r\n    11;\r\n    14];\r\nNextNumber= 28;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [39;\r\n    46;\r\n    39;\r\n    21;\r\n    46;\r\n    46;\r\n    45;\r\n    31;\r\n    47;\r\n    45;\r\n    39;\r\n    44;\r\n    47];\r\nNextNumber= 45;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n%%\r\nx =  [7;\r\n     8;\r\n    18;\r\n     7;\r\n     9;\r\n     2;\r\n    11;\r\n     2;\r\n     2;\r\n     2;\r\n    13;\r\n     4;\r\n     4;\r\n    13;\r\n    11;\r\n     6;\r\n     3;\r\n    15;\r\n    16;\r\n    17;\r\n     4;\r\n     7;\r\n    17;\r\n    12;\r\n     3;\r\n    12;\r\n     9;\r\n     3;\r\n    17;\r\n     2;\r\n     4;\r\n    17;\r\n     5;\r\n    18;\r\n     1;\r\n     4;\r\n    15;\r\n     2;\r\n    11;\r\n     6;\r\n    19;\r\n     4;\r\n     2;\r\n     1;\r\n    18;\r\n    15;\r\n    12;\r\n    17;\r\n    11;\r\n     2;\r\n     1;\r\n     3;\r\n    17;\r\n    15;\r\n     4;\r\n    12;\r\n    10;\r\n    11;\r\n    16;\r\n     4;\r\n     2;\r\n    13;\r\n    13;\r\n     8;\r\n    16;\r\n     2;\r\n     9;\r\n    19;\r\n     7;\r\n    15;\r\n    12;\r\n     5;\r\n    17;\r\n     6;\r\n     9;\r\n    16;\r\n     9;\r\n    11;\r\n     4;\r\n    12;\r\n     7;\r\n    12;\r\n     9;\r\n    18;\r\n     2;\r\n     8;\r\n    14];\r\nNextNumber= 4;\r\nassert(isequal(FindNextNumber(x),NextNumber))\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":2,"created_by":15013,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":16,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-05-16T23:24:44.000Z","updated_at":"2014-05-19T14:19:51.000Z","published_at":"2014-05-16T23:24:59.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eSo it goes like this, I give a number list and you find the next value!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eI found a way to do it, just wondering how many others can to!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThis could be a fun test of skill! Please try and see if you can get it!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[   x =  [ ...\\n    11;\\n     4;\\n    16;\\n     3;\\n     3;\\n    15;\\n     6;\\n    17;\\n    10;\\n    18;\\n     7;\\n    13;\\n    15;\\n     5;\\n    24;\\n     5;\\n     3;\\n     3];\\n NextValue = 3;\\n\\n %%Next value after x(1), so your finding the ? in sequence x = [?; 11; 4; 16; 3; ... 3];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eGood luck, just saying, it is tricky! Many have solved this, but the key is to find the pattern...\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2562,"title":"Juggling","description":"There is a notation system for \u003chttp://en.wikipedia.org/wiki/Juggling jugglers\u003e called \u003chttp://en.wikipedia.org/wiki/Siteswap siteswap\u003e\r\n\r\nLet consider the simplest version called vanilla siteswap.\r\n\r\nA siteswap pattern consist of a list of nonnegative integers being instructions for a juggler.\r\n\r\nWhile juggling, he throws up maximum one ball at the time at given by the pattern height (and then catches it after given periods). 0 means \"missing\", 1 is passing ball between hands,  2 is keeping ball for a moment (no toss), 3 is cascade toss, etc. (see \u003chttp://en.wikipedia.org/wiki/Siteswap Wikipedia\u003e)\r\n\r\nAfter one full cycle pattern is looped and can be performed continuously. This allows simple patterns to be very short, i.e. classical pattern for three balls noted as 333333... is written by only one 3.\r\n\r\nFor example pattern *51* uses three balls like that:     \r\n\r\n\u003c\u003chttp://upload.wikimedia.org/wikipedia/commons/thumb/3/35/Douche3b.gif/120px-Douche3b.gif\u003e\u003e\r\n\r\nand pattern *3* looks like this:\r\n\r\n\u003c\u003chttp://upload.wikimedia.org/wikipedia/commons/thumb/2/26/3-ball_cascade_movie.gif/220px-3-ball_cascade_movie.gif\u003e\u003e\r\n\r\nIn this problem we will consider such defined patterns. Catching and throwing up to one ball at a time is allowed. Given a vector of integers, determine if it is a valid pattern and return number of balls required (it's an average of pattern) or NaN instead.\r\n\r\n Input: [3]   Output:[3]\r\n\r\n Input: [441] Output:[3]\r\n\r\n Input: [521] Output:[NaN] (average is not an integer)\r\n\r\n Input: [321] Output:[NaN] (proper average, but balls meet together)\r\n\r\n(All illustrations courtesy of Wikipedia)","description_html":"\u003cp\u003eThere is a notation system for \u003ca href = \"http://en.wikipedia.org/wiki/Juggling\"\u003ejugglers\u003c/a\u003e called \u003ca href = \"http://en.wikipedia.org/wiki/Siteswap\"\u003esiteswap\u003c/a\u003e\u003c/p\u003e\u003cp\u003eLet consider the simplest version called vanilla siteswap.\u003c/p\u003e\u003cp\u003eA siteswap pattern consist of a list of nonnegative integers being instructions for a juggler.\u003c/p\u003e\u003cp\u003eWhile juggling, he throws up maximum one ball at the time at given by the pattern height (and then catches it after given periods). 0 means \"missing\", 1 is passing ball between hands,  2 is keeping ball for a moment (no toss), 3 is cascade toss, etc. (see \u003ca href = \"http://en.wikipedia.org/wiki/Siteswap\"\u003eWikipedia\u003c/a\u003e)\u003c/p\u003e\u003cp\u003eAfter one full cycle pattern is looped and can be performed continuously. This allows simple patterns to be very short, i.e. classical pattern for three balls noted as 333333... is written by only one 3.\u003c/p\u003e\u003cp\u003eFor example pattern \u003cb\u003e51\u003c/b\u003e uses three balls like that:\u003c/p\u003e\u003cimg src = \"http://upload.wikimedia.org/wikipedia/commons/thumb/3/35/Douche3b.gif/120px-Douche3b.gif\"\u003e\u003cp\u003eand pattern \u003cb\u003e3\u003c/b\u003e looks like this:\u003c/p\u003e\u003cimg src = \"http://upload.wikimedia.org/wikipedia/commons/thumb/2/26/3-ball_cascade_movie.gif/220px-3-ball_cascade_movie.gif\"\u003e\u003cp\u003eIn this problem we will consider such defined patterns. Catching and throwing up to one ball at a time is allowed. Given a vector of integers, determine if it is a valid pattern and return number of balls required (it's an average of pattern) or NaN instead.\u003c/p\u003e\u003cpre\u003e Input: [3]   Output:[3]\u003c/pre\u003e\u003cpre\u003e Input: [441] Output:[3]\u003c/pre\u003e\u003cpre\u003e Input: [521] Output:[NaN] (average is not an integer)\u003c/pre\u003e\u003cpre\u003e Input: [321] Output:[NaN] (proper average, but balls meet together)\u003c/pre\u003e\u003cp\u003e(All illustrations courtesy of Wikipedia)\u003c/p\u003e","function_template":"function n = siteswap(pattern)\r\n  n=mean(pattern);\r\nend","test_suite":"%%\r\npattern = 1;\r\ny_correct = 1;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = 2;\r\ny_correct = 2;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = 3;\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [3 3];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 5 1];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 5 2];\r\ny_correct = 4;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [3 2 1];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [3 1 2];\r\ny_correct = 2;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [4 4 1];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 2 1];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 5 5 0 0];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 3 1];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [6 4 5 1];\r\ny_correct = 4;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [7 3 3 3];\r\ny_correct = 4;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [7 1];\r\ny_correct = 4;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [5 3 1 4 5 3 0 5 5 2 0];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [3 4 2];\r\ny_correct = 3;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [7 7 1];\r\ny_correct = 5;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [1 4 0 3];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\npattern = [1 3 0 4];\r\ny_correct = 2;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n\r\n%%\r\na=randi(100)\r\npattern = [4*a, 0, 4*a-1, 1];\r\ny_correct = NaN;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\na=randi(100)\r\npattern = [4*a, 0, 1, 4*a-1];\r\ny_correct = 2*a;\r\nassert(isequaln(siteswap(pattern),y_correct))\r\n\r\n%%\r\nassert(isequaln(siteswap([6 0 1 5]),siteswap([6 0 5 1])))","published":true,"deleted":false,"likes_count":7,"comments_count":0,"created_by":14358,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":25,"test_suite_updated_at":"2014-09-12T09:06:19.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2014-09-08T12:38:05.000Z","updated_at":"2026-01-31T12:47:55.000Z","published_at":"2014-09-08T12:38:05.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/media/image1.gif\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/media/image2.gif\"}],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThere is a notation system for\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://en.wikipedia.org/wiki/Juggling\\\"\u003e\u003cw:r\u003e\u003cw:t\u003ejugglers\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e called\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://en.wikipedia.org/wiki/Siteswap\\\"\u003e\u003cw:r\u003e\u003cw:t\u003esiteswap\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eLet consider the simplest version called vanilla siteswap.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eA siteswap pattern consist of a list of nonnegative integers being instructions for a juggler.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eWhile juggling, he throws up maximum one ball at the time at given by the pattern height (and then catches it after given periods). 0 means \\\"missing\\\", 1 is passing ball between hands, 2 is keeping ball for a moment (no toss), 3 is cascade toss, etc. (see\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://en.wikipedia.org/wiki/Siteswap\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eWikipedia\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eAfter one full cycle pattern is looped and can be performed continuously. This allows simple patterns to be very short, i.e. classical pattern for three balls noted as 333333... is written by only one 3.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example pattern\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e51\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e uses three balls like that:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eand pattern\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e3\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e looks like this:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId2\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eIn this problem we will consider such defined patterns. Catching and throwing up to one ball at a time is allowed. Given a vector of integers, determine if it is a valid pattern and return number of balls required (it's an average of pattern) or NaN instead.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ Input: [3]   Output:[3]\\n\\n Input: [441] Output:[3]\\n\\n Input: [521] Output:[NaN] (average is not an integer)\\n\\n Input: [321] Output:[NaN] (proper average, but balls meet together)]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e(All illustrations courtesy of Wikipedia)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" 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Zero Zero Zero!!!","description":"Hello all,\r\nSo you have to find the largest section of zeros in a vector and then find the length of those zeros and there starting position...\r\nFor example:\r\n  \r\n  x = [1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 0 9 8 7 6 5 4 3 2 1];\r\n  %then the output is:\r\n  LP = [9 10] %[Length Position]\r\n  \r\n  %Or another example:\r\n  \r\n  x = [1 0 3 49 3 2 232 3 0 0 0 0 0 0 8 290 0 0 0 12 323 34];\r\n  %then the output is:\r\n  LP = [6 9]\r\n  \r\n  %Or another example:\r\n  \r\n  x = [1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 0];\r\n  %then the output is:\r\n  LP = [7 3];\r\n\r\nHave Fun!\r\n","description_html":"\u003cp\u003eHello all,\r\nSo you have to find the largest section of zeros in a vector and then find the length of those zeros and there starting position...\r\nFor example:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003ex = [1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 0 9 8 7 6 5 4 3 2 1];\r\n%then the output is:\r\nLP = [9 10] %[Length Position]\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e%Or another example:\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003ex = [1 0 3 49 3 2 232 3 0 0 0 0 0 0 8 290 0 0 0 12 323 34];\r\n%then the output is:\r\nLP = [6 9]\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003e%Or another example:\r\n\u003c/pre\u003e\u003cpre class=\"language-matlab\"\u003ex = [1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 0];\r\n%then the output is:\r\nLP = [7 3];\r\n\u003c/pre\u003e\u003cp\u003eHave Fun!\u003c/p\u003e","function_template":"function y = LengthAndPosnZeros(x)\r\n  y = x;\r\nend","test_suite":"%%\r\nx = [1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 0 9 8 7 6 5 4 3 2 1];\r\nLP = [9 10] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 0 3 49 3 2 232 3 0 0 0 0 0 0 8 290 0 0 0 12 323 34];\r\nLP = [6 9]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 0];\r\nLP = [7 3];\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 2 0 0];\r\nLP = [2 3] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 2 0 0 0 0 0 0 0 0 0 9 0 0 0 0 0 0];\r\nLP = [9 3] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 0 0 0 0 0 0 0 0 0 1];\r\nLP = [9 2] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [111 541 0 45 3 0 0 0 15 26 0 4 84 3 84 0 9];\r\nLP = [3 6] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n%%\r\nx = [1 0 1];\r\nLP = [1 2] %[Length Position]\r\nassert(isequal(LengthAndPosnZeros(x),LP))\r\n\r\n","published":true,"deleted":false,"likes_count":15,"comments_count":1,"created_by":15013,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":540,"test_suite_updated_at":"2013-08-08T19:35:25.000Z","rescore_all_solutions":false,"group_id":13,"created_at":"2013-08-08T18:54:26.000Z","updated_at":"2026-03-24T00:57:27.000Z","published_at":"2013-08-08T19:35:25.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHello all, So you have to find the largest section of zeros in a vector and then find the length of those zeros and there starting position... For example:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[x = [1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 0 9 8 7 6 5 4 3 2 1];\\n%then the output is:\\nLP = [9 10] %[Length Position]\\n\\n%Or another example:\\n\\nx = [1 0 3 49 3 2 232 3 0 0 0 0 0 0 8 290 0 0 0 12 323 34];\\n%then the output is:\\nLP = [6 9]\\n\\n%Or another example:\\n\\nx = [1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 0];\\n%then the output is:\\nLP = [7 3];]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHave Fun!\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":939,"title":"DNA Pattern Match:  Performance  Metric - Speed","description":"The Challenge is to Rapidly find matches of DNA sequences, Length=6, in a 1,800,000 long DNA file.\r\n\r\nAt \u003chttp://imacst.com/issues/volume-3issue-1/ IMACST\u003e the paper \u003chttp://imacst.com/web_documents/1202002.pdf An Intelligent and Efficient Matching Algorithm to Finding a DNA Pattern\u003e claimed an astounding time improvement from  9.94 seconds to 7.84 seconds, 21% time reduction, to match six segments of length 6 in a 1.8M long DNA file. Basic probability asserts 1.8M/4^6 * 6 = 2637 matches. The paper's test case produced 2346 matches. The method employed used text processing in C++. The paper's L=25 and L=50 cases will be later challenges.\r\n\r\nMatlab can achieve matching a six pattern set of L=6 in \u003c15 msec (i5/16GB). This is merely a 99.8% time reduction.\r\n\r\n\r\n*Challenge Description:*\r\nDNA is made of letters ACGT, \u003chttp://en.wikipedia.org/wiki/DNA wiki DNA\u003e, which for the purposes of this Matlab Cody Challenge are given values 0 thru 3. (ACGT= 0123)\r\n\r\n*Input:* [DNA, DNA_ID, Patterns]\r\n\r\n* DNA is a 1.8M long uint8 row vector of values 0 thru 3.\r\n* DNA_ID identifies the DNA segment being processed. Multiple calls using the same DNA_ID will be performed. The first call of a DNA_ID is not timed.\r\n* Patterns is an Nx6 uint8 array where each row corresponds to a search pattern.\r\n\r\n*Output:* Locations\r\n\r\nLocations of all start indices that match any of the patterns\r\n\r\n*Scoring:* Average Time (msec) for a block of L=6 patterns\r\n\r\nExample:\r\n\r\n* DNA= [0 1 2 3 3 2 1 0 1 2 3 3]\r\n* Pattern = [2 3 3 2 1 0]\r\n* Locations = [3]\r\n\r\n*Hints:*\r\n\r\n* Vectorization (Base 4 to Base 10 of 6 character words)\r\n* Bitshift/Reshape to create all words\r\n* Logical Indexing\r\n \r\n\r\nComing soon: Genome DNA sequencing of PhagePhix174 and Haempphilus Influenza","description_html":"\u003cp\u003eThe Challenge is to Rapidly find matches of DNA sequences, Length=6, in a 1,800,000 long DNA file.\u003c/p\u003e\u003cp\u003eAt \u003ca href=\"http://imacst.com/issues/volume-3issue-1/\"\u003eIMACST\u003c/a\u003e the paper \u003ca href=\"http://imacst.com/web_documents/1202002.pdf\"\u003eAn Intelligent and Efficient Matching Algorithm to Finding a DNA Pattern\u003c/a\u003e claimed an astounding time improvement from  9.94 seconds to 7.84 seconds, 21% time reduction, to match six segments of length 6 in a 1.8M long DNA file. Basic probability asserts 1.8M/4^6 * 6 = 2637 matches. The paper's test case produced 2346 matches. The method employed used text processing in C++. The paper's L=25 and L=50 cases will be later challenges.\u003c/p\u003e\u003cp\u003eMatlab can achieve matching a six pattern set of L=6 in \u0026lt;15 msec (i5/16GB). This is merely a 99.8% time reduction.\u003c/p\u003e\u003cp\u003e\u003cb\u003eChallenge Description:\u003c/b\u003e\r\nDNA is made of letters ACGT, \u003ca href=\"http://en.wikipedia.org/wiki/DNA\"\u003ewiki DNA\u003c/a\u003e, which for the purposes of this Matlab Cody Challenge are given values 0 thru 3. (ACGT= 0123)\u003c/p\u003e\u003cp\u003e\u003cb\u003eInput:\u003c/b\u003e [DNA, DNA_ID, Patterns]\u003c/p\u003e\u003cul\u003e\u003cli\u003eDNA is a 1.8M long uint8 row vector of values 0 thru 3.\u003c/li\u003e\u003cli\u003eDNA_ID identifies the DNA segment being processed. Multiple calls using the same DNA_ID will be performed. The first call of a DNA_ID is not timed.\u003c/li\u003e\u003cli\u003ePatterns is an Nx6 uint8 array where each row corresponds to a search pattern.\u003c/li\u003e\u003c/ul\u003e\u003cp\u003e\u003cb\u003eOutput:\u003c/b\u003e Locations\u003c/p\u003e\u003cp\u003eLocations of all start indices that match any of the patterns\u003c/p\u003e\u003cp\u003e\u003cb\u003eScoring:\u003c/b\u003e Average Time (msec) for a block of L=6 patterns\u003c/p\u003e\u003cp\u003eExample:\u003c/p\u003e\u003cul\u003e\u003cli\u003eDNA= [0 1 2 3 3 2 1 0 1 2 3 3]\u003c/li\u003e\u003cli\u003ePattern = [2 3 3 2 1 0]\u003c/li\u003e\u003cli\u003eLocations = [3]\u003c/li\u003e\u003c/ul\u003e\u003cp\u003e\u003cb\u003eHints:\u003c/b\u003e\u003c/p\u003e\u003cul\u003e\u003cli\u003eVectorization (Base 4 to Base 10 of 6 character words)\u003c/li\u003e\u003cli\u003eBitshift/Reshape to create all words\u003c/li\u003e\u003cli\u003eLogical Indexing\u003c/li\u003e\u003c/ul\u003e\u003cp\u003eComing soon: Genome DNA sequencing of PhagePhix174 and Haempphilus Influenza\u003c/p\u003e","function_template":"function Locations = find_DNA(DNA, DNA_ID, Patterns)\r\n persistent DNA_ID_loaded  % add other DNA created variables\r\n Locations=[];\r\n if isempty(DNA_ID_loaded) || DNA_ID~=DNA_ID_loaded\r\n  % Perform initialization actions on DNA vector - optional\r\n  DNA_ID_loaded=DNA_ID;\r\n  \r\n end % DNA_ID Processing\r\n\r\n\r\n\r\n \r\nend\r\n\r\n\r\n\r\n\r\n","test_suite":"%%\r\nfeval(@assignin,'caller','score',0);\r\n%%\r\n% Functionality Section\r\nPass=1;\r\nw=6;\r\nDNA=randi(4,1,1800000,'uint8')-1;\r\nPatterns=randi(4,12,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:6,:); % Take first 6 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nDNA_ID=1;\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\nif isempty(Locations),Pass=0;end\r\nif max(size(Locations))\u003c1024,Pass=0;end\r\nfor i=1:size(Locations,1)\r\n      Pass=Pass \u0026\u0026 ismember(DNA(Locations(i,end):Locations(i,end)+w-1),Patterns,'rows');\r\n    end\r\n\r\nDNA=randi(4,1,1800000,'uint8')-1;\r\nPatterns=randi(4,24,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:12,:); % Take first 6 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nDNA_ID=2;\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\nif isempty(Locations),Pass=0;end\r\nif max(size(Locations))\u003c1024,Pass=0;end\r\nfor i=1:size(Locations,1)\r\n      Pass=Pass \u0026\u0026 ismember(DNA(Locations(i,end):Locations(i,end)+w-1),Patterns,'rows');\r\n    end\r\n\r\n\r\nassert(isequal(Pass,1))\r\n%%\r\n% Timing Section\r\nDNA=randi(4,1,1800000,'uint8')-1;\r\nPatterns=randi(4,12,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:6,:); % Take first 6 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nDNA_ID=1;\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\n\r\nt0=clock;\r\nfor i=1:10\r\n Locations = find_DNA(DNA, DNA_ID, Patterns);\r\nend\r\ndt1=etime(clock,t0)*1000; % msec conversion\r\nfprintf('Your Set 1 Time = %i msec\\n',floor(dt1))\r\n\r\n\r\nPatterns=randi(4,24,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:12,:); % Take first 12 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nt0=clock;\r\nfor i=1:10\r\n Locations = find_DNA(DNA, DNA_ID, Patterns);\r\nend\r\ndt2=etime(clock,t0)*1000; % msec conversion\r\nfprintf('Your Set 2 Time = %i msec\\n',floor(dt2))\r\n\r\n\r\n% New DNA Set\r\nDNA=randi(4,1,1800000,'uint8')-1;\r\nPatterns=randi(4,12,6,'uint8')-1; % Create more than needed\r\nPatterns=unique(Patterns,'rows','stable'); % Elim dupes but maintain random\r\nPatterns=Patterns(1:6,:); % Take first 6 random vectors\r\nPatterns=unique(Patterns,'rows'); % Place in order for easier debugging\r\n\r\nDNA_ID=2;\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\nLocations = find_DNA(DNA, DNA_ID, Patterns);\r\n\r\nt0=clock;\r\nfor i=1:10\r\n Locations = find_DNA(DNA, DNA_ID, Patterns);\r\nend\r\ndt3=etime(clock,t0)*1000; % msec conversion\r\nfprintf('Your Set 3 Time = %i msec\\n',floor(dt3))\r\n\r\n\r\nfeval(@assignin,'caller','score',min(400,floor(double(dt1+dt2+dt3)/30)));\r\n","published":true,"deleted":false,"likes_count":1,"comments_count":0,"created_by":3097,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":9,"test_suite_updated_at":"2012-09-10T03:41:37.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2012-09-10T00:09:00.000Z","updated_at":"2025-11-21T09:02:33.000Z","published_at":"2012-09-10T03:40:23.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe Challenge is to Rapidly find matches of DNA sequences, Length=6, in a 1,800,000 long DNA file.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eAt\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://imacst.com/issues/volume-3issue-1/\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eIMACST\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e the paper\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://imacst.com/web_documents/1202002.pdf\\\"\u003e\u003cw:r\u003e\u003cw:t\u003eAn Intelligent and Efficient Matching Algorithm to Finding a DNA Pattern\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e claimed an astounding time improvement from 9.94 seconds to 7.84 seconds, 21% time reduction, to match six segments of length 6 in a 1.8M long DNA file. Basic probability asserts 1.8M/4^6 * 6 = 2637 matches. The paper's test case produced 2346 matches. The method employed used text processing in C++. The paper's L=25 and L=50 cases will be later challenges.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eMatlab can achieve matching a six pattern set of L=6 in \u0026lt;15 msec (i5/16GB). This is merely a 99.8% time reduction.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eChallenge Description:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e DNA is made of letters ACGT,\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"http://en.wikipedia.org/wiki/DNA\\\"\u003e\u003cw:r\u003e\u003cw:t\u003ewiki DNA\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e, which for the purposes of this Matlab Cody Challenge are given values 0 thru 3. (ACGT= 0123)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eInput:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e [DNA, DNA_ID, Patterns]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDNA is a 1.8M long uint8 row vector of values 0 thru 3.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDNA_ID identifies the DNA segment being processed. Multiple calls using the same DNA_ID will be performed. The first call of a DNA_ID is not timed.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePatterns is an Nx6 uint8 array where each row corresponds to a search pattern.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eOutput:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e Locations\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eLocations of all start indices that match any of the patterns\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eScoring:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e Average Time (msec) for a block of L=6 patterns\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eDNA= [0 1 2 3 3 2 1 0 1 2 3 3]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ePattern = [2 3 3 2 1 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