Question

please help me to get with the scenerio mentioned
If A is a matrix of (n,m) how to group n(rows) in a random manner such that the values present in (n) in each row should be i...

plus de 8 ans il y a | 1 réponse | 0

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Question

Please help me to overcome the error of the following code
A = diag([1 2 3 4 5 6 7 8 9]); N_G=3;%No of group B = cell(N_G,1); sumB = cell(N_G,1); for i=1:1:N_G n=...

plus de 8 ans il y a | 2 réponses | 0

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Question

OFDMA grouping of users
could anyone help me to execute the following code as I am getting error N_UE=[2 4 6 8 10]; for t= 1:length(N_UE) ...

plus de 8 ans il y a | 1 réponse | 0

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Question

grouping n number of groups in random manner
If A is an array of 50 rows and 100 columns how to group 50 rows in a random manner into n number of groups.

plus de 8 ans il y a | 1 réponse | 0

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How to solve the error
Please help me to execute the following code clear all; clc; N_UE = [2 4 6 8 10]; % number of users N_SC = [20 30...

plus de 8 ans il y a | 1 réponse | 0

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Question

Basic understanding on matlab
could anyone tell me what is the difference between array and matrix with example. if A=[1 2;3 4] and B=[5 6;7 8] how A*B=...

plus de 8 ans il y a | 3 réponses | 0

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Question

Please help me to find the solution of the issue.
C = Columns 1 through 10 0 0 0 0 0 0 0 ...

plus de 8 ans il y a | 1 réponse | 0

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Question

C=(users,subcarriers) where users=[2 4 6 8 10] and subcarriers=[20 30 40 50 60] how grouping of users can be done with respect to sharing their subcarriers values among the group
clear all; clc; numUsers = 50; N_UE = 1 : numUsers s = N_UE(randperm(length(N_UE))) numGroups = 10; divisio...

plus de 8 ans il y a | 1 réponse | 0

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Question

please help me to execute the following code
Could anyone help me to execute the following code as i am unable to execute it clear all; clc; N_UE=[2 4 6 8 10]; N_SC=[20 ...

plus de 8 ans il y a | 1 réponse | 0

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Question

random grouping of users and subcarriers
Please anyone help me to execute the following code. clear all; clc; N_UE=[2 4 6 8 10]; N_SC=[20 30 40 50 60]; t= 1:l...

plus de 8 ans il y a | 1 réponse | 0

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Question

Grouping and sharing of subcarriers in a random manner
Could anyone tell me how to group rows(row 1 with row 2 or row 3 with row 5 or row2 and row 3 with row5) in a random manner such...

plus de 8 ans il y a | 1 réponse | 0

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Question

grouping along with subcarrier sharing
clear all; clc; numUsers = 10; % numsubcarriers=100; % 1:length(N_UE) N_UE = 1 : numUsers % N_SC = 1 : numsu...

plus de 8 ans il y a | 1 réponse | 0

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Question

random grouping of users
C = 0 0 0 0.0453 0 0 0 0 0 0.0741 0.0831 0...

plus de 8 ans il y a | 1 réponse | 0

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Question

Sharing of subcarriers with respect to user grouping
If number of users are 50 and subcarriers are 200. how come random grouping of users an be made with the result of sharing thei...

plus de 8 ans il y a | 1 réponse | 0

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Question

user grouping with subcarrier sharing
A=[1 0 0 0 0 0;0 2 0 0 0 0;0 0 3 0 0 0;0 0 0 4 0 0;0 0 0 0 5 0;0 0 0 0 0 6] [ii,jj] = find(A) B = A B(sub2ind(size(A),rem(ii ...

plus de 8 ans il y a | 1 réponse | 0

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Question

Please help me to get rid of this error.
siz = size(G) idx = sub2ind(siz, randi([1,4], 1, siz(2)), 1:siz(2)); C = zeros(siz); C(idx) = G(idx) [ii,jj] = find(C) ...

plus de 8 ans il y a | 1 réponse | 0

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How to get the output for the below code
could anyone help me how to get the output. siz = size(G) idx = sub2ind(siz, randi([1,4], 1, siz(2)), 1:siz(2)); C ...

plus de 8 ans il y a | 1 réponse | 0

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How to solve the error of replication factors
could anyone tell me Why I am getting the following error and how it can be solved Error using repmat Replication factors mu...

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Question

How to solve Error using repmat
If C = 0 0 0.0244 0 0.0260 0 0.0136 0 0 0 0.1738 ...

plus de 8 ans il y a | 2 réponses | 0

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Question

Matrix manipulation using reshape
If A= 1 0 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 ...

plus de 8 ans il y a | 1 réponse | 0

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sharing of numbers in the matrix
If A=[0.1 0 0.2 0 0 0 0 0;0 0 0 0.3 0.4 0 0 0;0 0.5 0 0 0 0 0 0.6;0 0 0 0 0 0.7 0.8 0] I want to have B=[0.1 0 0....

plus de 8 ans il y a | 2 réponses | 0

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Question

grouping the users thereby sharing the subcarriers
Nuser=4; Nsubcarrier=10; G is a matrix of (users,subcarriers)%image attached below C is subcarrier allocation to users %i...

plus de 8 ans il y a | 1 réponse | 0

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Question

how grouping of users can be done
N_UE=[1 2 3 4 5 6 7 8 9 10] If there are 10 users in the system i need to form 5 groups such that 2 users are present in each...

plus de 8 ans il y a | 2 réponses | 0

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Question

could anyone tell me how to group users in a random manner such that sharing of subcarriers takes place.
N_UE=[2 4 6 8 10]; N_SC=[20 30 40 50 60]; -------------------------------- for t= 1:length(N_UE) for r = 1:length(...

plus de 8 ans il y a | 1 réponse | 0

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Question

Please help me to execute the following code as i am unable to get the exact result
UE=[2 4 6 8 10]; SC=[20 40 50 60 80]; for t=1:length(UE) for r=1:length(SC) G=rand(UE(t),SC(r)); siz = size(G) ...

plus de 8 ans il y a | 1 réponse | 0

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Question

how to overcome matrix dimensions must agree error
I have attached the screen shot taken from coding pls help to solve this issue.

plus de 8 ans il y a | 1 réponse | 0

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Question

could anyone help me to execute the following code as i am unable to get the result.
UE=[2 4 6 8 10]; SC=[20 40 50 60 80]; for t=1:length(UE) for r=1:length(SC) G=rand(UE(t),SC(r)); B=zeros(UE(t),...

plus de 8 ans il y a | 1 réponse | 0

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Question

Could anyone help me how to solve the following issue.
If i run this code i am getting the result such that in each column i am getting one values out of 5 and the rest are zero.If ...

plus de 8 ans il y a | 1 réponse | 0

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Question

could anyone help me to execute the following code as i am unable to get the result
N_UE=[2 4 6 8 10]; N_SC=[20 30 40 50 60]; as=4; bs=10; for t= 1:length(N_UE) for r = 1:length(N_SC) Lsigma=a...

plus de 8 ans il y a | 1 réponse | 0

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Question

please help me to execute the following code
if N_UE=[2 4 6 8 10]; N_SC=[20 30 40 50 60]; for t= 1:length(N_UE) for r = 1:length(N_SC) G=rand(t,r) end end B= zeros(t,...

plus de 8 ans il y a | 1 réponse | 0

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