Réponse apportée Graph smoothing not working properly
"x" is not monotonous, therefore, you should use this kind of form:
yy1 = smooth(y,0.1,'loess');
presque 3 ans il y a | 0
| A accepté
Réponse apportée Compare two columns having different values.
I will suggest the table join to do it:
tbla=table;
tblb=table;
tbla.var={'a','b','c','d','e'}';
tblb.var={'b','c','d','e','...