Answered

Datenum with a.m. and p.m.

Assuming there is ".m. EST" attached to each "timestamp" at the end. You can follow the steps: Step-1 Replace ".m. EST" to just...

Datenum with a.m. and p.m.

Assuming there is ".m. EST" attached to each "timestamp" at the end. You can follow the steps: Step-1 Replace ".m. EST" to just...

21 jours ago | 1

| accepted

Answered

Trying to count number of cells between two columns

In the code that you have shared whichDistance is an empty matrix. So when you do raw(whichDistance, :)=[]; raw array doesn't ...

Trying to count number of cells between two columns

In the code that you have shared whichDistance is an empty matrix. So when you do raw(whichDistance, :)=[]; raw array doesn't ...

21 jours ago | 0

Answered

index array to access the value in matrix

Step1 - Convert the subscript to indeces using x & y(Hint: sub2ind) Step2 - Calculate values of IM for calculated indeces Step...

index array to access the value in matrix

Step1 - Convert the subscript to indeces using x & y(Hint: sub2ind) Step2 - Calculate values of IM for calculated indeces Step...

22 jours ago | 0

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Answered

Writing a Function Code

Try: function out = timeconv(t) y = datestr(round(t/900)*900/(24*60*60),'HH:MM AM'); end

Writing a Function Code

Try: function out = timeconv(t) y = datestr(round(t/900)*900/(24*60*60),'HH:MM AM'); end

22 jours ago | 0

Answered

How to find the maximum value for each 24 rows in an array?

According to the comments, you have provided, this will produce the desired output : yd = max(max(mn2t)); % first find maximum ...

How to find the maximum value for each 24 rows in an array?

According to the comments, you have provided, this will produce the desired output : yd = max(max(mn2t)); % first find maximum ...

23 jours ago | 1

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Answered

how to index a cell array?

Try : area_r = arrayfun(@(a) cellfun(@(c) trapz(c(c>=0)),a.elevation,'UniformOutput',false), K, 'UniformOutput',false); I hope...

how to index a cell array?

Try : area_r = arrayfun(@(a) cellfun(@(c) trapz(c(c>=0)),a.elevation,'UniformOutput',false), K, 'UniformOutput',false); I hope...

23 jours ago | 0

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Answered

Getting an empty plot

Try: clear; x = linspace(5.62,31.62); p = -10*log10((1+ (31.5844 * (x.^2)) + (11.24*x*cos(pi)))./ (32.5844*(1 + (x.^2)))); % ...

Getting an empty plot

Try: clear; x = linspace(5.62,31.62); p = -10*log10((1+ (31.5844 * (x.^2)) + (11.24*x*cos(pi)))./ (32.5844*(1 + (x.^2)))); % ...

25 jours ago | 0

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Answered

Legend in a "for loop"

Try : for ii=1:length(giri) figure(3); plot(m(indice_m_0:loc(ii)),psic_pos(ii,indice_m_0:loc(ii)),'DisplayName',['ii = ',num2...

Legend in a "for loop"

Try : for ii=1:length(giri) figure(3); plot(m(indice_m_0:loc(ii)),psic_pos(ii,indice_m_0:loc(ii)),'DisplayName',['ii = ',num2...

25 jours ago | 1

Answered

How can i return a value based on mutliple fields?

Try: id = find(N2.Components(:,1) == 290 & N2.Components(:,2) == 296); PowerConsequences_out = N2.PowerConsequences(id); ICTC...

How can i return a value based on mutliple fields?

Try: id = find(N2.Components(:,1) == 290 & N2.Components(:,2) == 296); PowerConsequences_out = N2.PowerConsequences(id); ICTC...

25 jours ago | 0

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Answered

Sub function error within main function

Try: function volSAtsa(l , w, h) vol = volume (l, w, h); [a1, a2, a3] = sides(l, w , h); tsa = total(a1 , a2 , a3); out(vol...

Sub function error within main function

Try: function volSAtsa(l , w, h) vol = volume (l, w, h); [a1, a2, a3] = sides(l, w , h); tsa = total(a1 , a2 , a3); out(vol...

26 jours ago | 0

Answered

How can I make the numbers count horizontal instead of vertical?

Try a = input('What is the size of the square array? (Enter one number): ','s'); sq = str2num(a); elements = 0; for x = 1:sq...

How can I make the numbers count horizontal instead of vertical?

Try a = input('What is the size of the square array? (Enter one number): ','s'); sq = str2num(a); elements = 0; for x = 1:sq...

26 jours ago | 0

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Answered

Plotting daily mean values of temperature

Assuming there are no leap years in this period of time, I think you have a vector of dimesion (35040x1) (2samples*24hrs*365days...

Plotting daily mean values of temperature

Assuming there are no leap years in this period of time, I think you have a vector of dimesion (35040x1) (2samples*24hrs*365days...

26 jours ago | 0

Answered

In an assignment A(I) = B, the number of elements in B and I must be the same.

Your: A(17:240) % is a vector of 224 elements ((240-17+1)x1) while B % is a vector of 18 elements (18x1) that's why you are...

In an assignment A(I) = B, the number of elements in B and I must be the same.

Your: A(17:240) % is a vector of 224 elements ((240-17+1)x1) while B % is a vector of 18 elements (18x1) that's why you are...

28 jours ago | 0

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Answered

how to modify input-output script to show how many line were copied.

Try: ifn = input( 'input file name: ', 's' ); ofn = input('output file name: ', 's' ); ih = fopen( ifn, 'r' ); oh = fopen(...

how to modify input-output script to show how many line were copied.

Try: ifn = input( 'input file name: ', 's' ); ofn = input('output file name: ', 's' ); ih = fopen( ifn, 'r' ); oh = fopen(...

28 jours ago | 0

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Answered

Surface area of sphere integral form

Limits should be [0, pi/2] & fun should be sin fun = @(theta) sin(theta); S = 4*pi*R^2*(integral(fun,theta_1,theta_2/2)); % t...

Surface area of sphere integral form

Limits should be [0, pi/2] & fun should be sin fun = @(theta) sin(theta); S = 4*pi*R^2*(integral(fun,theta_1,theta_2/2)); % t...

28 jours ago | 0

Answered

How to extract Month string from day_Month_Year time variable and create a new quarterly time index?

If I understand the question correctly, this should work : Month_variable = datestr(datenum('Oct_01_2019'),'mm'); I hope it he...

How to extract Month string from day_Month_Year time variable and create a new quarterly time index?

If I understand the question correctly, this should work : Month_variable = datestr(datenum('Oct_01_2019'),'mm'); I hope it he...

29 jours ago | 0

| accepted

Answered

problem in running time of my project

I changed one simple thing, it was working more efficiently for me: clc clear; tic; Input = [ 5 12 0.02 4 ...

problem in running time of my project

I changed one simple thing, it was working more efficiently for me: clc clear; tic; Input = [ 5 12 0.02 4 ...

29 jours ago | 0

| accepted

Answered

How can I format a large cell of data into one big column underneath a (predeclared) title?

Try this: my_storage = titles; %foo, bar, fubar header titles my_storage_mat = [transpose(theS...

How can I format a large cell of data into one big column underneath a (predeclared) title?

Try this: my_storage = titles; %foo, bar, fubar header titles my_storage_mat = [transpose(theS...

29 jours ago | 0

| accepted

Answered

How do I delete multiple elements from a column array using a while loop?

This should do the job: A = [1 0 1 0 1 0 1 0]'; A(A==0) = []

How do I delete multiple elements from a column array using a while loop?

This should do the job: A = [1 0 1 0 1 0 1 0]'; A(A==0) = []

30 jours ago | 1

Answered

How do I create a matrix surrounding the center element?

Try: n = 5; A = zeros(n); [r,c] = find(A==0); sub = [r,c]-(n+1)/2; for i = 1:(n-1)/2 ind = find((sub(:,1)==-i&sub(:,2)>=-i...

How do I create a matrix surrounding the center element?

Try: n = 5; A = zeros(n); [r,c] = find(A==0); sub = [r,c]-(n+1)/2; for i = 1:(n-1)/2 ind = find((sub(:,1)==-i&sub(:,2)>=-i...

environ un mois ago | 1

| accepted

Answered

a zero finding function

Hint: (for small x). You can rewrite the equation . I think rest you can solve using linear algebra.

a zero finding function

Hint: (for small x). You can rewrite the equation . I think rest you can solve using linear algebra.

environ un mois ago | 0

Answered

How can i solve?

Below code worked for me : rng default tsim = 0:0.002:10; % simulation time Amp = {-7,-5,-3,-1,1,3,5,7}; % Amplitudes dt = 0...

How can i solve?

Below code worked for me : rng default tsim = 0:0.002:10; % simulation time Amp = {-7,-5,-3,-1,1,3,5,7}; % Amplitudes dt = 0...

environ un mois ago | 0

| accepted

Answered

How can I move through an array and a vector that need to be compared?

My undersanding for the question. For example you have a coordinates of 4 test planes (X) & coordinate for a separate referenc...

How can I move through an array and a vector that need to be compared?

My undersanding for the question. For example you have a coordinates of 4 test planes (X) & coordinate for a separate referenc...

environ un mois ago | 0

Answered

Summation of vectors: use of sum function in loop

I think Newvalue=(1/t)*sqrt(Value); should be outside the for loop : vector=[1;2;3;4;5;6]; vectortwo=[1;3;4;5;6;8]; s=leng...

Summation of vectors: use of sum function in loop

I think Newvalue=(1/t)*sqrt(Value); should be outside the for loop : vector=[1;2;3;4;5;6]; vectortwo=[1;3;4;5;6;8]; s=leng...

environ un mois ago | 1

| accepted

Answered

Converting a string to datenum format

Try: DateString = '2011-08-31T21:16:01.948Z'; RepExp = '[a-zA-Z]'; % want to replace any alphabet, indicated by [a-zA-Z] RepS...

Converting a string to datenum format

Try: DateString = '2011-08-31T21:16:01.948Z'; RepExp = '[a-zA-Z]'; % want to replace any alphabet, indicated by [a-zA-Z] RepS...

environ un mois ago | 0

Answered

Problem with computing integral of a function

Using some info from this question, which you have posted again. My understanding is that you want to calculate Phi at each n & ...

Problem with computing integral of a function

Using some info from this question, which you have posted again. My understanding is that you want to calculate Phi at each n & ...

environ un mois ago | 0

Answered

How to get text file from char

Try : clc; clear; tic fid = fopen('myFile.txt','w'); % open text file b = sprintf('0123456789'); d = 0; T = char; for ii...

How to get text file from char

Try : clc; clear; tic fid = fopen('myFile.txt','w'); % open text file b = sprintf('0123456789'); d = 0; T = char; for ii...

environ un mois ago | 0

Answered

How to write a LOOP for this case?

I think this is the continuation of this question. So, once you create struture as mentioned in the above answer, you can use:...

How to write a LOOP for this case?

I think this is the continuation of this question. So, once you create struture as mentioned in the above answer, you can use:...

environ un mois ago | 1

Answered

How to exclude some additional points from plot legend?

You can assign plot to different variables and when you use legend only use handles of the assigned variables. For e.g. figure(...

How to exclude some additional points from plot legend?

You can assign plot to different variables and when you use legend only use handles of the assigned variables. For e.g. figure(...

environ un mois ago | 0

Answered

How to summarize this code?

You can try to create structure for the data of different years: for i = 1:length(precips) precip.(['y',num2str(i+1981)]) ...

How to summarize this code?

You can try to create structure for the data of different years: for i = 1:length(precips) precip.(['y',num2str(i+1981)]) ...

environ un mois ago | 0

| accepted