Solve eigenvalue PDE problem
[v,l] = pdeeig(b,p,e,t,c,a,d,r)
[v,l] = pdeeig(K,B,M,r)
–∇ · (c∇u) + au = λdu on Ω
or the system PDE eigenvalue problem
on a geometry described by p, e, and t, and with boundary conditions given by b.
v is an eigenvector matrix. For the scalar case each column in v is an eigenvector of solution values at the corresponding node points from p. For a system of dimension N with np node points, the first np rows of v describe the first component of v, the following np rows of v describe the second component of v, and so on. Thus, the components of v are placed in blocks v as N blocks of node point rows.
b describes the boundary conditions of the PDE problem. For the recommended way of specifying boundary conditions, see Steps to Specify a Boundary Conditions Object. For all methods of specifying boundary conditions, see Boundary Condition Specification.
The eigenvalue PDE problem is a homogeneous problem, i.e., only boundary conditions where g = 0 and r = 0 can be used. The nonhomogeneous part is removed automatically.
The geometry of the PDE problem is given by the mesh data p, e, and t. For details on the mesh data representation, see Mesh Data.
The coefficients c, a, d of the PDE problem can be given in a wide variety of ways. In the context of pdeeig the coefficients cannot depend on u nor t, the time. For a complete listing of all options, see Scalar PDE Coefficients and Coefficients for Systems of PDEs.
K ui = λB´MBui
u = Bui
with Real(λ) in the interval in r.
Compute the eigenvalues less than 100 and corresponding eigenmodes for
–∇u = λu,
on the geometry of the L-shaped membrane. Then display the first and sixteenth eigenmodes.
[p,e,t] = initmesh('lshapeg'); [p,e,t] = refinemesh('lshapeg',p,e,t); [p,e,t] = refinemesh('lshapeg',p,e,t); [v,l] = pdeeig('lshapeb',p,e,t,1,0,1,[-Inf 100]); l(1) % first eigenvalue pdesurf(p,t,v(:,1)) % first eigenmode figure membrane(1,20,9,9) % the MATLAB function figure l(16) % sixteenth eigenvalue pdesurf(p,t,v(:,16)) % sixteenth eigenmode
In the standard case c and d are positive in the entire region. All eigenvalues are positive, and 0 is a good choice for a lower bound of the interval. The cases where either c or d is zero are discussed next.
If d = 0 in a subregion, the mass matrix M becomes singular. This does not cause any trouble, provided that c > 0 everywhere. The pencil (K,M) has a set of infinite eigenvalues.
If c = 0 in a subregion, the stiffness matrix K becomes singular, and the pencil (K,M) has many zero eigenvalues. With an interval containing zero, pdeeig goes on for a very long time to find all the zero eigenvalues. Choose a positive lower bound away from zero but below the smallest nonzero eigenvalue.
If there is a region where both c = 0 and d = 0, we get a singular pencil. The whole eigenvalue problem is undetermined, and any value is equally plausible as an eigenvalue.
Some of the awkward cases are detected by pdeeig. If the shifted matrix is singular, another shift is attempted. If the matrix with the new shift is still singular a good guess is that the entire pencil (K,M) is singular.
If you try any problem not belonging to the standard case, you must use your knowledge of the original physical problem to interpret the results from the computation.