# Check Model Assumptions for Chow Test

This example shows how to check the model assumptions for a Chow test. The model is of U.S. gross domestic product (GDP), with consumer price index (CPI) and paid compensation of employees (COE) as predictors. The forecast horizon is 2007 - 2009, just before and after the 2008 U.S. recession began.

Load the U.S. macroeconomic data set.

`load Data_USEconModel`

The time series in the data set contain quarterly, macroeconomic measurements from 1947 to 2009. For more details, a list of variables, and descriptions, enter `Description` at the command line.

Extract the predictors and the response from the table. Focus the sample on observations taken from 1960 - 2009.

```idx = year(DataTimeTable.Time) >= 1960; dates = DataTimeTable.Time(idx); y = DataTimeTable.GDP(idx); X = DataTimeTable{idx,["CPIAUCSL" "COE"]}; varNames = ["CPIAUCSL" "COE" "GDP"];```

Identify forecast horizon indices.

`fHIdx = year(dates) >= 2007;`

Plot all series individually. Identify the periods of recession.

```figure tiledlayout(2,2) nexttile plot(dates,y) title(varNames{end}); xlabel("Year"); axis tight; datetick; recessionplot; for j = 1:size(X,2) nexttile plot(dates,X(:,j)) title(varNames{j}); xlabel("Year"); axis tight; datetick; recessionplot; end```

All variables appear to grow exponentially. Also, around the last recession, a decline appears. Suppose that a linear regression model of GDP onto CPI and COE is appropriate, and you want to test whether there is a structural change in the model in 2007.

### Check Chow Test Assumptions

Chow tests rely on:

• Independent, Gaussian-distributed innovations

• Constancy of the innovations variance within subsamples

• Constancy of the innovations across any structural breaks

If a model violates these assumptions, then the Chow test result might not be correct, or the Chow test might lack power. Investigate whether the assumptions hold. If any do not, preprocess the data further.

Fit the linear model to the entire series. Include an intercept.

`Mdl = fitlm(X,y);`

`Mdl` is a `LinearModel` model object.

Draw two histogram plots using the residuals: one with respect to fitted values in case order, and the other with respect to the previous residual.

```figure tiledlayout(2,1) nexttile plotResiduals(Mdl,"lagged"); nexttile plotResiduals(Mdl,"caseorder");```

Because the scatter plot of residual vs. lagged residual forms a trend, autocorrelation exists in the residuals. Also, residuals on the extremes seem to flare out, which suggests the presence of heteroscedasticity.

Conduct Engle's ARCH test at 5% level of significance to assess whether the innovations have conditional heteroscedasticity with ARCH(1) effects. Supply the table of residals and specify the raw residuals.

`StatTbl = archtest(Mdl.Residuals,DataVariable="Raw")`
```StatTbl=1×6 table h pValue stat cValue Lags Alpha _____ ______ ______ ______ ____ _____ Test 1 true 0 109.37 3.8415 1 0.05 ```

`h = 1` suggests to reject the null hypothesis that the entire residual series has no conditional heteroscedasticity.

Apply the log transformation to all series that appear to grow exponentially to reduce the effects of heteroscedasticity.

```y = log(y); X = log(X);```

To account for autocorrelation, create predictor variables for all exponential series by lagging them by one period.

```LagMat = lagmatrix([X y],1); X = [X(2:end,:) LagMat(2:end,:)]; % Concatenate data and remove first row fHIdx = fHIdx(2:end); y = y(2:end);```

Based on the residual diagnostics, choose this linear model for GDP

`${\text{GDP}}_{t}={\beta }_{0}+{\beta }_{1}{\text{CPIAUCSL}}_{t}+{\beta }_{2}{\text{COE}}_{t}+{\beta }_{3}{\text{CPIAUCSL}}_{t-1}+{\beta }_{4}{\text{COE}}_{t-1}+{\beta }_{5}{\text{GDP}}_{t-1}+{\epsilon }_{t}.$`

${\epsilon }_{t}$ should be a Gaussian series of innovations with mean zero and constant variance ${\sigma }^{2}$.

Diagnose the residuals again.

```Mdl = fitlm(X,y); figure tiledlayout(2,1) nexttile plotResiduals(Mdl,"lagged"); nexttile plotResiduals(Mdl,"caseorder");```

`StatTbl = archtest(Mdl.Residuals,DataVariable="Raw")`
```StatTbl=1×6 table h pValue stat cValue Lags Alpha _____ _______ ______ ______ ____ _____ Test 1 false 0.28133 1.1607 3.8415 1 0.05 ```
```SubMdl = {fitlm(X(~fHIdx,:),y(~fHIdx)) fitlm(X(fHIdx,:),y(fHIdx))}; subRes = {SubMdl{1}.Residuals.Raw SubMdl{2}.Residuals.Raw}; [hVT2,pValueVT2] = vartest2(subRes{1},subRes{2})```
```hVT2 = 0 ```
```pValueVT2 = 0.1645 ```

The residual plots and tests suggest that the innovations are homoscedastic and uncorrelated.

Conduct a Kolmogorov-Smirnov test to assess whether the innovations are Gaussian.

`[hKS,pValueKS] = kstest(Mdl.Residuals.Raw/std(Mdl.Residuals.Raw))`
```hKS = logical 0 ```
```pValueKS = 0.2347 ```

`hKS = 0` suggests to not reject the null hypothesis that the innovations are Gaussian.

For the distributed lag model, the Chow test assumptions appear valid.

### Conduct Chow Test

Treating 2007 and beyond as a post-recession regime, test whether the linear model is stable. Specify that the break point is the last quarter of 2006. Because the complementary subsample size is greater than the number of coefficients, conduct a break point test.

```bp = find(~fHIdx,1,'last'); chowtest(X,y,bp,'Display','summary');```
```RESULTS SUMMARY *************** Test 1 Sample size: 196 Breakpoint: 187 Test type: breakpoint Coefficients tested: All Statistic: 1.3741 Critical value: 2.1481 P value: 0.2272 Significance level: 0.0500 Decision: Fail to reject coefficient stability ```

The test fails to reject the stability of the linear model. Evidence is inefficient to infer a structural change between `Q4-2006` and `Q1-2007`.