LSB in audio stegnography
Afficher commentaires plus anciens
% Embed message length in the first 16 samples
% (I don't understand how. Can any one explain?)
str = dec2bin(length(message),16);
if length(message) < length(y)
for a = 1 : length(str)
y(a, nbits-1) = str(a);
end
else
disp('error')
end
I don't understand how they are embedding here. Please help me.
1 commentaire
Walter Roberson
le 31 Mar 2016
Note: the proper term is "steganography" not "stegnography"
Réponse acceptée
Plus de réponses (2)
Muhammad fayyaz
le 29 Avr 2014
0 votes
2 commentaires
Walter Roberson
le 29 Avr 2014
Assume that the original signal has been converted into binary by using dec2bin(). dec2bin() returns an array of characters, each one being the character '0' or the character '1'. Then y(a,nbits-1) is a straight forward replacement of one element of the array with one element of the character vector "str".
Somewhere after this section of code, you will find a call to bin2dec(y) . That operation will take the character array y and convert the representation back into decimal numbers.
Muhammad fayyaz
le 30 Avr 2014
Muhammad fayyaz
le 1 Mai 2014
Modifié(e) : Walter Roberson
le 31 Mar 2016
Catégories
En savoir plus sur Numbers and Precision dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!